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noname [10]
2 years ago
13

Explain why the larger the hydrocarbon molecule is the more

Chemistry
2 answers:
RideAnS [48]2 years ago
6 0

Answer:

Longer hydrocarbon molecules have a stronger intermolecular force. More energy is needed to move them apart so they have higher boiling points . This makes them less volatile and therefore less flammable

Rama09 [41]2 years ago
5 0
What do you mean????
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explain why it is a common laboratory procedure to heat analytical reagents and store them in a dessicated atmosphere (a sealed
Readme [11.4K]

Explanation:

Most reagent forms are going to absorb water from the air; they're called "hygroscopic".  Water presence can have a drastic impact on the experiment being performed  For fact, it increases the reagent's molecular weight, meaning that anything involving a very specific molarity (the amount of molecules in the final solution) will not function properly.

Heating will help to eliminate water, although some chemicals don't react well to heat, so it shouldn't be used for all.  A dessicated environment is simply a means to  "dry."  That allows the reagent with little water in the air to attach with.

6 0
2 years ago
This is a chemistry question that i don't know how to do. Need some help
koban [17]
C₀=8.10M
c₁=5.28M
v₀=1.58 L
v₁-?

n=c₀v₀=c₁v₁

v₁=c₀v₀/c₁

v₁=8.10*1.58/5.28=2.42 L 
5 0
3 years ago
Based on table n, uranium-238 and uranium-235 have different
Amanda [17]

According to table N, the isotopes uranium-238 and uranium-235 have different half lives.

<h3>What are radioactive nuclides?</h3>

Radioactive nuclides are those nuclides that are able to undergo radioactive decay. They have specific modes of decay that is peculiar to each isotope.

Hence, according to table N, the isotopes uranium-238 and uranium-235 have different half lives.

Learn more about uranium-238:brainly.com/question/9099776

#SPJ1

4 0
1 year ago
Which type of wave interaction is shown by the water waves in the photo?
Neko [114]
I think A but I’m not sure so
8 0
2 years ago
Read 2 more answers
Draw the product formed when the compound shown below undergoes a reaction with hbr in ch2cl2. interactive 3d display mode
zysi [14]

Answer : The complete question is attached in the answer.


Explanation : In the given question an alkene is treated with alkylhalide in presence of methylene dichloride it gives a corresponding alkylbromide species.


The mechanism follows markonikov's addition rule, and the major product thus formed is bromine which is attached to least substituted carbon atom ad minor is bromine attached to highly substituted carbon atom.


4 0
2 years ago
Read 2 more answers
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