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Andrei [34K]
3 years ago
14

Your science class decides to conduct an experiment to learn more about ice. You set one ice cube on the counter at room tempera

ture, and another, same-sized ice cube in the class refrigerator. You predict that since it is warmer on the counter at room temperature, the ice cube on the counter will melt faster. What result would confirm this prediction? A)When the counter ice cube is melted, the refrigerator ice cube is not finished melting. B)When the counter ice cube is melted, the refrigerator ice cube is also finished melting. C)When the counter ice cube is not quite melted, the refrigerator ice cube is finished melting. D)When the counter ice cube is not quite melted, the refrigerator ice cube is not finished melting.
Physics
2 answers:
ipn [44]3 years ago
7 0
This would be A. If the counter cube is finished while the refrigerator isn't, that confirms the hypothesis.
anzhelika [568]3 years ago
7 0

Answer:

A) When the counter ice is melted, the refrigerator ice cube is not finished melting.

Explanation:

Considering the varying temperatures, the temperature on the counter at room temperature is higher than that in the refrigerator and as such, the counter ice cube will melt faster than the refrigerator ice cube.

The refrigerator ice cube will also melt, but at a very slow rate compared to the counter ice cube, therefore, when the counter cube is completely melted, the refrigerator ice cube is not finished melting.

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The 10-lb block has a speed of 4 ft/s when the force of f=(8t2)f=(8t2) lb is applied. determine the velocity of the block when t
KatRina [158]

The velocity of the block when t == 2 s is 60.7 ft./sec.

Equations of Motion.

Here the friction is F_f = \mu_k N = 0.2 N

+ \uparrow \sum F_y = ma_y; \quad N – 10 = \frac { 10 } { 32.2 }(0) \quad N = 10 lb \\ \begin{aligned} \underrightarrow{ + } \sum F_x = ma_x; \quad 8t^2 – 0.2(10 &) = \frac { 10 } { 32.2 }a \\ & a = 3.22(8t^2 – 2) ft/s^2 \end{aligned}

Kinematics.

The velocity of the block as a function of t can be determined by

integrating dv = adt using the initial condition v = 4 ft./s at t = 0.

\int_{ 4 ft/s }^{ v } dv = \int_0^t 3.22(8t^2 – 2)dt \\ \begin{aligned} v – &4 = 3.22 (\frac 8 3 t^3 – 2t) \\ & v = \{8.5867t^3 – 6.44t + 4 \} ft/s \end{aligned}

The displacement as a function of t can be determined by integrating

ds = vdt using

the initial condition s = 0 at t = 0

\int_0^s ds = \int_0^t (8.5867t^3 – 6.44t + 4)dt \\ s = \{2.1467t^4 – 3.22t^2 + 4t \} ft

at t = 2 sec

s = 30 ft.

Thus, at s = 30 ft.,

\begin{aligned} v &= 8.5867(2.0089^3) – 6.44(2.0089) + 4 \\ &= 60.67 ft/s \\ &= 60.7 ft/s \end{aligned}

Kinematics is a subfield of physics, developed in classical mechanics, that describes the motion of points, bodies (objects), and systems of bodies (groups of objects) without considering the forces that cause them to move.

Kinematics, as a field of study, is often referred to as the "geometry of motion" and is occasionally seen as a branch of mathematics. A kinematics problem begins by describing the geometry of the system and declaring the initial conditions of any known values of position, velocity and/or acceleration of points within the system.

Then, using arguments from geometry, the position, velocity and acceleration of any unknown parts of the system can be determined. The study of how forces act on bodies falls within kinetics, not kinematics. For further details, see analytical dynamics.

Learn more about kinematics here : brainly.com/question/24486060

#SPJ4

5 0
1 year ago
What method has detected the most extrasolar planets so far?
Sedaia [141]
<h2>Answer: The Transit  method</h2>

Detecting extrasolar planets by direct observation (with a telescope) is a complicated task. This is because any planet constitutes an extremely dim light source compared to the star around which it orbits.

So, to detect this extremely dim source is quite difficult due to the glare of the star's light that dulls it.

In this sense, scientists and astronomers have made several methods to find these extrasolar planets, among which the most successful has been the transit method.

This method is based on <u>astronomical transit</u>, a phenomenon in which a body (a planet in this case) passes in front of a larger one (the star), blocking (eclipsing) its vision to some extent.

It should be noted that this is the method currently used in the search for extrasolar planets. Space agencies such as ESA (Europe) and NASA (USA) have put into orbit satellites with extremely sensitive photometric sensors to observe even the smallest variations of intensity of a star due to the passage of a planet.

5 0
3 years ago
Which interaction of nature depends on the distance through which it acts and is involved in beta decay? a. strong c. electromag
USPshnik [31]

The answer is weak.  The interaction of nature that will depend on the distance through the way it acts and involved in beta decay is the weak interaction or the weak force. This interaction is the responsible for radioactive decay which also plays a significant role in nuclear fission.

5 0
3 years ago
A gas is confined to a cylinder under constant atmospheric pressure, as illustrated in the following figure. When the gas underg
GarryVolchara [31]
From the first law of thermodynamics, we use the equation expressed as:

ΔH = Q + W

where Q is the heat absorbed of the system and W is the work done.

We calculate as follows:

ΔH = Q + W
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Hope this answers the question. Have a nice day.
7 0
3 years ago
Read 2 more answers
7. Which best describes the energy change th pushes a large rock down a hill?
svlad2 [7]

Answer:

B

Explanation:

Gravitational Energy is the energy of position or place. A rock resting at the top of a hill contains gravitational Potential energy. Hydropower, such as water in a reservoir behind a dam, is an example of gravitational potential energy.

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3 years ago
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