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3 years ago

How ar intrusive igneous bodies classified

1 answer:

3 0

1. D
Intrusive igneous bodies are rock bodies that are formed due to the flow of magma. In classifying igneous bodies, their size, shape, and relationship(s) with the surrounding rock layers are all considered.

2. B.
A batholith is the largest type of igneous body and it extends to unknown depths within the Earth's crust. These bodies are the size of mountains and are composed mainly of intermediate rock types like granite.

3. B
This igneous body is formed when magma intrudes into rock fractures and then crystalizes there. Through this crystallization, the newly formed rock cuts through the existing rock layers.

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a crane does 9,500 J of work to lift a crate straight up using a force of 125 N. how high does the crane lift the crate?

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Answer:

The crane lifts the crate up to 76 m high

Explanation:

Work Done by a Force

The work done by a force of magnitude F that displaces an object by a distance y is given by

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2 years ago

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3 years ago

I need help with this question how to solve it for Brass and Cooper

Ksenya-84 [330]

Take into account that density and relative density are given by:

$\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}$

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

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Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:

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$\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}$

Cooper:

$\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}$

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