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iren [92.7K]
3 years ago
13

. A cathode ray tube (CRT) is a device that produces a focused beam of electrons in a vacuum. The electrons strike a phosphor-co

ated glass screen at the end of the tube, which produces a bright spot of light. The position of the bright spot of light on the screen can be adjusted by deflecting the electrons with electrical fields, magnetic fields, or both. Although the CRT tube was once commonly found in televisions, computer displays, and oscilloscopes, newer appliances use a liquid crystal display (LCD) or plasma screen. You still may come across a CRT in your study of science. Consider a CRT with an electron beam average current of 25.00μA25.00μA . How many electrons strike the screen every minute?
Physics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

The value is n=  9.375 *10^{15} \  electrons

Explanation:

From the question we are told that

  The average current is  I  =  25.0 \mu A = 25.0 *10^{-6} \  A

Generally the quantity of charge (electron )  is mathematically represented as

       Q =  ne

Here e is the charge on a single electron with value e = 1.60  *10^{-19} \  C

   Generally current is mathematically represented as

     I  = \frac{Q}{t}

=>   I  = \frac{ne}{t}

Here t is time which is given as 1 minutes =  60  seconds

  and  n is the number of electrons

So

      25.0 *10^{-6}  = \frac{ n* 1.60  *10^{-19}}{60}

=>    60  * 25.0 *10^{-6} =  n* 1.60  *10^{-19}

=>    n=  \frac{60  * 25.0 *10^{-6} }{ 1.60  *10^{-19} }

=>    n=  9.375 *10^{15} \  electrons

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Consider the numbers 23.68 and 4.12. The sum of these numbers has ____ significant figures, and the product of these numbers has
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A 1.0 kg football is given an initial velocity at ground level of 20.0 m/s [37° above horizontal]. It gets blocked just after re
brilliants [131]
1) Data:

Vo = 20 m/s
α = 37°
Yo = 0
Y = 3m

2) Questions: V at Y = 3m and X at Y = 3 m

3) Calculate components of the initial velocity

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Voy = Vo * sin(37°) = 12.04 m/s

4) Formulas

Vx = constant = 15.97 m/s

X = Vx * t

Vy = Voy - g*t

Y = Yo + Voy * t - g (t^2) / 2

5) Calculate t when Y = 3m (first time)

Use g ≈ 9.8 m/s^2

3 = 12.04 * t - 4.9 t^2

=> 4.9 t^2 - 12.04t + 3 = 0

Use the quadratic equation to solve the equation

=> t = 0.28 s and t = 2.18s

First time => t = 0.28 s.

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Vy = 12.04 m/s  - 9.8 * 0.28s = 9.3 m/s

7) Calculate V:

V = √ [ (Vx)^2 + (Vy)^2 ] = √[ (15.97m/s)^2 + (9.30 m/s)^2 ] = 18.48 m/s

tan(β) = Vy/Vx = 9.30 / 15.97 ≈ 0.582 => β ≈ arctan(0.582) ≈ 30°

Answer: V ≈ 18.5 m/s, with angle ≈ 30°

8) Calculate X at t = 0.28s

X = Vx * t = 15.97 m/s * 0.28s = 4,47m ≈ 4,5m

Answer: X ≈ 4,5 m
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ich statement best describes the fundamental difference between spiral and elliptical galaxies? Spiral galaxies are more massive
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