There will be four unpaired electrons
The metal complex is [FeX₆]³⁻
X being the halogen ligand
X = F, CL, Br, and I
The oxidation of metal state is +3
The ground state configuration is
₂₆Fe =Is² 2s²2p⁶ 3s² 3p⁶ 3d⁶ 4s²
Metal, Fe(III) ion electron configures
₂₆Fe³⁺ = Is2 2s² 2p⁶ 3s² 3p⁶ 3d⁵
Answer:
I = 578A
Explanation:
The magnitude of the peak value of the induced current flowing in a coild is given by


Where
I= current
N = Number of loops
angular velocity
R= Resistance
B = Magnetic field
A = Area
Replacing our values we have that,


B) Copper atoms have a loosely held free electron in their outer shell that is able to move freely to other atoms.
An insulator which is also called a 'dielectric'.