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iren [92.7K]
3 years ago
13

. A cathode ray tube (CRT) is a device that produces a focused beam of electrons in a vacuum. The electrons strike a phosphor-co

ated glass screen at the end of the tube, which produces a bright spot of light. The position of the bright spot of light on the screen can be adjusted by deflecting the electrons with electrical fields, magnetic fields, or both. Although the CRT tube was once commonly found in televisions, computer displays, and oscilloscopes, newer appliances use a liquid crystal display (LCD) or plasma screen. You still may come across a CRT in your study of science. Consider a CRT with an electron beam average current of 25.00μA25.00μA . How many electrons strike the screen every minute?
Physics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

The value is n=  9.375 *10^{15} \  electrons

Explanation:

From the question we are told that

  The average current is  I  =  25.0 \mu A = 25.0 *10^{-6} \  A

Generally the quantity of charge (electron )  is mathematically represented as

       Q =  ne

Here e is the charge on a single electron with value e = 1.60  *10^{-19} \  C

   Generally current is mathematically represented as

     I  = \frac{Q}{t}

=>   I  = \frac{ne}{t}

Here t is time which is given as 1 minutes =  60  seconds

  and  n is the number of electrons

So

      25.0 *10^{-6}  = \frac{ n* 1.60  *10^{-19}}{60}

=>    60  * 25.0 *10^{-6} =  n* 1.60  *10^{-19}

=>    n=  \frac{60  * 25.0 *10^{-6} }{ 1.60  *10^{-19} }

=>    n=  9.375 *10^{15} \  electrons

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Answer:

Explanation:

66.2mi/h to m/s

\frac{1609m}{1mi}×\frac{66.2mi}{1h}×\frac{1h}{60min}×\frac{1min}{60s}

  1. mi will go with mi
  2. h with h
  3. min with min
  4. m/s is left

\frac{1609*66.2}{60*60}= 29.58772222

Pls make sure of the way of solving to be sure...

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4 years ago
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4 years ago
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nirvana33 [79]

Answer:

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Now, let's see if it is possible.

Suppose you have a soundwave approaching the car, the car needs to cancel the soundwaves as the soundwaves approach to the surface, to do it, you need to create another wave that is equal in amplitude, but with a change of phase of pi.

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Another problem is that, as you know, the sound propagates as spherical waves, this means that the wavefront of a wave produced far away will have a bigger radius than the soundwave produced by the car, then we never will have a situation where the wavefront is canceled: This means that we only can cancellate the sound in some areas of the car, and we still will have some sound in other parts of the car.

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3 years ago
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Oliga [24]

Answer:

<h3>The answer is 3.81 kg</h3>

Explanation:

The mass of the dog can be found by using the formula

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