Answer:
0.219N
Explanation:
Given data
mass= 7.3kg
acceleration= 0.03m/s^2
We know that
F=ma
substitute
F= 7.3*0.03
F= 0.219N
Hence the applied force is 0.219N
Survey research method uses questionnaires to collect information about the participants in a study.It is commonly used method of collecting information about a population of interest.
Answer:
2500 kg/m³
Explanation:
The density is ...
(107 g)/((12.2 cm)(3.7 cm)(0.95 cm)) = 107/42.883 g/cm³ ≈ 2.5 g/cm³
In kg/m³, the density is ...
(2.5 g/cm³)×(1 kg/(1000 g))×(100 cm/m)³ = 2500 kg/m³
The conversion from CGS to MKS units of density is done using the usual method of units conversion. The conversion factor multipliers each change the units without changing the value, because their numerator is equal to the denominator.
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2 significant figures are used because the block dimensions have a precision of 2 significant figures.
v initial = 0m/s
v final = 40m/s
t = 5s
d = ?
The kinematic equation which relates these quantities:
d = 1/2(vinitial + vfinal)t
d = 0.5(0+40)(5)
d = 100m
