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4 years ago

I need help, I don't understand the question

Chemistry

1 answer:

Oduvanchick [21]4 years ago

3 0

Remember this.

Ionic molecules has ionic bonds
Nonpolar molecules has dispersion (Van del Waals)
Polar molecules could either have hydrogen bonding or Dipole-Dipole. Hydrogen bonding is when you have F, O or N with H, every other polar molecule is dipole-dipole.

a. polar- dipole-dipole
b. polar- hydrogen bonding
c. nonpolar- dispersion
d. nonpolar- dispersion
e. polar- dipole-dipole
f. polar-dipole-dipole
g. nonpolar- dispersion
h. polar- hydrogen bonding.

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What is ph level of acid rain

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Answer:

Normal, clean rain has a pH value of between 5.0 and 5.5, which is slightly acidic. However, when rain combines with sulfur dioxide or nitrogen oxides—produced from power plants and automobiles—the rain becomes much more acidic. Typical acid rain has a pH value of 4.0.

Explanation:

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3 years ago

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3 years ago

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Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

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3 years ago

Whats the main difference between a double replacement reaction and a single replacement

aivan3 [116]

Answer:

a single-replacement reaction replaces one element for another in a compound. A double-replacement reaction exchanges the cations, or the anions, of two ionic compounds.

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3 years ago