Question

Sixty-three grams of copper reacted with 32 grams of sulfur. this chemical reaction produced the compound copper sulfide. what was the mass of this compound?

Answer 1

The mass of, $Cu_2S$, compound formed is 77.9g

62 grams of copper reacted with 32grams of sulfur to form copper sulfide.

$Cu + S_2 \rightarrow CuS_2$

stoichiometry of Cu to S is 2:1

We need to find the limiting reactant

Molar mass of copper = 63.5 g/mol

Molar mass of Sulfur = 32 g/mol

Number of moles of Copper =  $\dfrac{mass} {molar mass } = 0.99mole$

Number of moles of Sulfur = $\dfrac{mass} {molar mass} = \dfrac{32g} {32g/mol} = 1 mole$

Since copper have lesser number of moles, therefore the limiting reagent is copper so the amount of product formed depends on amount of Cu present

stoichiometry of Copper to $Cu_2S$ is 2:1

0.99 mol of Copper forms = $\dfrac{0.99} {2}$  = 0.49 mol of $Cu_2S$

Mass of $Cu_2S$ produced = Number of moles  $\times$ Molar mass                

Mass of $Cu_2S$ produced = 0.49 mol $\times$ 159 g/mol = 77.9g

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