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Artemon [7]
2 years ago
8

Encountering problems during separation/purification is a very common issue in organic synthesis, but these steps are crucial to

isolate your desired product.
a. True
b. False
Chemistry
1 answer:
Rus_ich [418]2 years ago
8 0
True is the correct answer! your welcome! :)
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What is the percent composition of H in <br> C<br> 10<br> H<br> 20<br> ?
wolverine [178]
11.19%. This should be right. I have no doubt that you will get it right.
7 0
2 years ago
What is the ph of the solution prepared by dissolving 0.927 mol hcl in enough water to make a 150 l aqueous solution?
Brilliant_brown [7]

Answer:

The answer to your question is pH = 2.2

Explanation:

Data

pH = ?

moles of HCl = 0.927

volume = 150 l

Process

1.- Calculate the Molar concentration of HCl

Molarity = moles / volume (L)

Molarity = 0.927 / 150

              = 0.00618

2.- Calculate the pH

pH = -log [HCl]

Substitution

pH = -log [0.00618]

Result

pH = 2.2

8 0
2 years ago
And with solution...
Tems11 [23]

Answer:

The answer to your question is: V = 6.93 L

Explanation:

Data

N₂ = 5.6 g

Volume of NH₃ = ?

                              14 g of N   ----------------  1 mol

                              5.6 g -----------------------   x

                             x = (5.6 x 1) / 14 = 0.4 mol of N

Reaction

                                N₂    +     3H₂    ⇒    2NH₃

                                1 mol of N₂   ----------------  2 moles of NH₃

                                0.4 mol of N₂ --------------   x

                               x = (0.4 x 2) / 1

                               x = 0.8 mol of NH₃

Formula

                 PV = nRT

P = 5200 torr = 6.84 atm

V = ?

n = 0.8

R = 0.082 atm L/ mol °K

T = 450°C = 723°K

Substitution

                     V = (0.8)(0.082)(723) / 6.84

                     V = 6.93 L

7 0
3 years ago
What is the name of an acid with the formula HNO2?
Step2247 [10]
HNO2 is the formula for Nitrous Acid
8 0
3 years ago
Calculate the % composition of the unknown liquid using your most precise result. It is a mixture of ethanol (D[ETOH] = 0.7890 g
Rufina [12.5K]

% composition of ethanol = 34.51%

% composition of water  = 65.49%

<h3>What is density?</h3>

A material's density is defined as its mass per unit volume.

Given data:

The density of ethanol = 0.7890 g/mL

The density of water = 0.9982 g/mL

The density of mixture = 0.926 g/mL

Let the % composition of ethanol = x

Let the % composition of water = 100-x

Now density of the mixture

\frac{Mass}{Volume}

Mass = \frac{percent  \;of  \;ethanol  \;X  \;density  \;of  \;ethanol  \;+  \\ \;percent  \;of  \;water X  \;density  \;of  \;water}{100}

0.926 = \frac{x X  0.7890 g/mL  \;+  (100-x) X  0.9982 g/mL}{100}

x= 34.51 %

Hence,

% composition of ethanol = 34.51%

% composition of water = 65.49%

Learn more about the density here:

brainly.com/question/952755

#SPJ1

8 0
1 year ago
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