When an aqueous solution of lead(ii) nitrate (Pb(NO₃)₂) is mixed with an aqueous solution of sodium iodide (NaI), an aqueous solution of sodium nitrate (NaNO₃) and a yellow solid, lead iodide (PbI₂),
are formed.
The balanced equation for the reaction is:
Pb(NO₃)₂(aq)+2NaI(aq)→2NaNO₃(aq)+PbI₂(s)
The coefficient of Oxygen in the balanced reaction : 3
<h3>Further explanation</h3>
Given
Reaction(unbalanced)
C2H4+ O2--> CO2+H2O
Required
The coefficient of Oxygen
Solution
C₂H₄+ aO₂⇒ bCO₂+cH₂O
C, left=2, right=b⇒b=2
H, left=4, right=2c⇒2c=4⇒c=2
O, left=2a, right=2b+c⇒2a=2b+c⇒2a=2.2+2⇒2a=6⇒a=3
The equation becomes :
<em>C₂H₄+ 3O₂⇒ 2CO₂+2H₂O</em>
Answer:
0.20M
Explanation:
Molarity (by definition) = moles / Volume in Liters
∴Molarity = 0.030mol/0.15Liter = 0.20M
