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nlexa [21]
4 years ago
10

Bonjour, quelqu’un pourrait-il m’aider avec ce numéro , (#13)

Chemistry
1 answer:
suter [353]4 years ago
7 0

Answer:

La réponse ce trouve en bas

Explanation:

13 a) Oui, ce possible parce la solubilité du sel dans l'eau a 60° est majeur que 50g du sel en 150 ml d'eau (333.3 g/L). Dans la graphique la solubilité est  de 370 g/L.

b) Jusqu'au 30°C, (30°, 360g(L), ce trouvent ces points dans la ligne rouge.

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Read 2 more answers
What is the pH of 0.26 M ammonium ion? NH4+(aq) + H2O(1) NH3(aq) + H30* (aq) a. 4.33 b.9.25 c. 3.87 d. 4.92 e. 4.75
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Answer:

b) pH = 9.25

Explanation:

  • NH4+(aq)  +  H2O(l)  ↔  NH3(aq)  +  H3O+(aq)
  • NH3 + H2O ↔ NH4+  +  OH-
  • 2 H2O ↔ H3O+  +  OH-

⇒ Kb = [ NH4+ ] * [ OH- ] / [ NH3 ] = 1.86 E-5......from literature

mass balance NH4+:

⇒ M NH4+ = [ NH4+ ] - [ OH- ]

∴ [ NH3 ] ≅ M NH4+ = 0.26 M

⇒ Kb = (( 0.26 + [ OH- ] )) * [ OH- ] / 0.26 = 1.86 E-5

⇒ 0.26 [ OH-] + [ OH- ]² = 4.836 E-6

⇒ [ OH- ]² + 0.26 [ OH- ] - 4.836 E-6 = 0

⇒ [ OH- ] = 1.859 E-5 M

⇒ pOH = - Log ( 1.859 E-5 )

⇒ pOH = 4.7305

⇒ pH = 14 - pOH = 9.269

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