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2 years ago

Compare and contrast type 1 and type 2 diabetes

2 answers:

4 0

Type 1 diabetes: Its a chronic condition in which the pancreas produces little or no insulin. The symptoms include: increased thirst, frequent urination, hunger, fatigue, and blurred vision. This can be cured if treated propertly.

Type 2 diabetes: A chronic condition that affects the way the body processes blood sugar (glucose). the symptoms are the same as Type 1 but sometimes for type 2 you won't be able to feel any symptoms.

Hope this helped :)

Brrunno [24]2 years ago

4 0

Answer:

In type 1, the body does not produce insulin.

In type 2, the body does produce insulin, but the body’s cells do not recognize its presence or the body doesn’t produce enough insulin.

Type 1 is diagnosed in children and is fairly rare.

Type 2 is the most common type of diabetes.

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Select ALL the correct answers.

tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$

$10th\ run = 9$

So:

$B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

Required

Select all true statements

(a) & (d) Median Comparisons

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$ $B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

$n = 9$ $n = 10$

Arrange the data:

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$Median = \frac{n + 1}{2}th$

$Median = \frac{9 + 1}{2}th$ $Median = \frac{10 + 1}{2}th$

$Median = \frac{10}{2}th$ $Median = \frac{11}{2}th$

$Median = 5th$ $Median = 5.5}th$ --- average of 5th and 6th

$Median = 2$ $Median = \frac{2+2}{2} = 2$

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$n = 9$ $n = 10$

First, calculate the lower quartile (Q1)

$Q_1 = \frac{n + 1}{4}th$ [Odd n] $Q_1 = \frac{n}{4}th$ [Even n]

$Q_1 = \frac{9 + 1}{4}th$ $Q_1 = \frac{10}{4}th$

$Q_1 = \frac{10}{4}th$ $Q_1 = 2.5$

$Q_1 = 2.5th$

This means that:

$Q_1 = 2nd + 0.5(3rd - 2nd)$ $Q_1 = 2nd + 0.5(3rd - 2nd)$

$Q_1 = 1 + 0.5(1- 1)$ $Q_1 = 1+ 0.5(1 - 1)$

$Q_1 = 1$ $Q_1 = 1$

Next, calculate the upper quartile (Q3)

$Q_3 = \frac{3}{4}(n + 1)th$ [Odd n] $Q_3 = \frac{3}{4}(n)th$ [Even n]

$Q_3 = \frac{3}{4}(9 + 1)th$ $Q_3 = \frac{30}{4}th$

$Q_3 = \frac{30}{4}th$ $Q_3 = 7.5th$

$Q_3 = 7.5th$

This means that:

$Q_3 = 7th + 0.5(8th- 7th)$ $Q_3 = 7th + 0.5(8th- 7th)$

$Q_3 = 2 + 0.5(3- 2)$ $Q_3 = 2+ 0.5(4 - 2)$

$Q_3 = 2.5$ $Q_3 = 3$

The interquartile range is $IQR = Q_3 - Q_1$

So, we have:

$IQR = 2.5 - 1$ $IQR = 3 - 1$

$IQR = 1.5$ $IQR =2$

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

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2 years ago

The rate limiting reaction of aerobic respiration involves the phosphorylation of __________ by the enzyme _______ . The rate at

Ahat [919]

Answer:

Explanation:

The rate limiting reaction of aerobic respiration involves the phosphorylation of fructose phosphate by the enzyme phosphofructokinase. The rate at which this enzyme makes product is [increased, decreased] when ATP levels rise because the molecule ATP binds to an allosteric site on the enzyme and acts as a direct inhibitor. When ATP levels fall AMP binds to the allosteric site of phosphofructokinase. This interaction leads to an increase of cellular ATP, so that this is an example of a negative feedback loop.

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2 years ago

A scientist conducts an experiment to test the effects of light on earthworm activity. Which is a variable in this experiment? l

777dan777 [17]

<span>I believe it is light, but this is kind of a confusing question. Technically there is a independent and dependent variable in the question. The variable being manipulated is light, and the earthwork activity depends on the light. </span>

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2 years ago

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How is melting water turning it from the ice to liquid water an example of a physical property

Ivan

Answer:

A. Melting the substance doses not change the substance

Explanation:

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2 years ago

Can a person live without salivary glands

Delvig [45]

Answer:

Sublingual glands are located under the tongue and the submandibular glands are beneath the jaw. Without these crucial salivary glands, the mouth would not be able to maintain tooth health nor moisture of any kind.

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2 years ago