Change in speed = 20 m/s
Time for the change = 10 sec
Average acceleration during the time =
(change in speed) / (time for the change)
(20 m/s) / (10 sec) = <em>2 m/s²</em>
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
power ratings basically just compare with how many watts are used, like a tackle in football compares to a car engine
Answer:
1. Magnetic force = 4.56*10^-12 N
2. Acceleration = 5.01 *10^18 m/s^2
3. A) The direction of the moving electron will change but its speed will remain constant.
Explanation:
Given Data:
B = 0.0040 T North
q = 1.6*10^-19 C
Mass of electron = 9.1*10^-31 kg
V = 9.5% of speed of light
= 9.5% *3*10^8
= 28.5*10^6 m/s west
So, B and v are perpendicular to each other.
Therefore, ∅ = 90°
1, Calculating the magnetic force using the formula;
F = qvBsin∅
= 1.6*10^-19 * 28.5*10^6*sin90
= 4.56*10^-12 N
Therefore, the strength of the force = 4.56*10^-12 N
2. Calculating acceleration using the formula;
F = ma
a = F/m
= 4.56*10^-12 /9.1*10^-31
= 5.01 *10^18 m/s^2
3. A) The direction of the moving electron will change but its speed will remain constant.
R 3/4 = (R3 * R4) / (R3 + R 4) = ( 9 * 18 ) /(9 + 18 ) = 162 / 27 = 6 Ohms
R e = R 1 + R 2 + R 3/4 + R 5 = 3 + 6 + 6 + 15 = 30 Ohms
I = U / Re = 90 V / 30 Ohms = 3 A
Finally for the voltage U 3/4 ( the parallel portion of the circuit ):
U 3/4 = 6 Ohms * 3 A = 18 V
Answer: 18 V