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77julia77 [94]
3 years ago
12

A fortnite is an old English term that means 14 days. How many seconds are in a fortnite?

Physics
2 answers:
BartSMP [9]3 years ago
7 0

I assume you mean fortnight? haha

Anyway, to answer this question, we need to have prior knowledge of time measurements. You should know that there are 60 seconds in a minute, 60 minutes in an hour, and 24 hours in a day.

Therefore, if a fortnight is 14 days, we should multiply 14 by 24 to work out how many hours there are:

14 × 24 = 336 hours

Now, we should multiply 336 by 60 to work out the number of minutes:

336 × 60 = 20,160 minutes

And finally, we just need to multiply 20,160 by 60 again to work out the number of seconds:

20,160 × 60 = 1,209,600 seconds

And there you go! Your final answer is 1,209,600 seconds.

Andrew [12]3 years ago
3 0

Answer

1.21e+6

Explanation:

That is the way to properly write it

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The spring of a spring gun has force constant k = 400 N/m and negligible mass. The spring is compressed 6.00 cm and a ball with
nikdorinn [45]

Answer:

A) v = 6.93 m/s

B) v = 4.9 m/s

C) x_m = 0.015m

D) v_max = 5.2 m/s

Explanation:

We are given;

x = 6 cm = 0.06 m

k = 400 N

m = 0.03 kg

F = 6N

A) from work energy law, work dome by the spring on ball which now became a kinetic energy is;

Ws = K.E = ½kx²

Similarly, kinetic energy of ball is;

K.E = ½mv²

So, equating both equations, we have;

½kx² = ½mv²

Making v the subject gives;

v = √(kx²/m)

Plugging in the relevant values to give;

v = √((400 × 0.06²)/0.03)

v = √48

v = 6.93 m/s

B) If there is friction, the total work is;

Ws = ½kx² - - - (1)

Work of the ball is;

Wb = KE + Wf

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Combining both equations, we have;

½mv² + fx = ½kx²

Plugging in the relevant values, we have;

(½ × 0.03 × v²) + (6 × 0.06) = ½ × 400 × 0.06²

0.015v² + 0.36 = 0.72

0.015v² = 0.72 - 0.36

v² = 0.36/0.015

v = √24

v = 4.9 m/s

C) The speed is greatest where the acceleration stops i.e. where the net force on the ball is zero. (ie spring force matches 6.0N friction)

So, from F = Kx;

(x is measured into barrel from end where F = 0)

Thus; 6.0 = 400x

x_m = 6/400

x_m = 0.015m from the end after traveling 0.045m

D) Initial force on ball = (Kx - F) =

[(400 x 0.06) - 6.0] = 18N

Final force on ball = 0N

Mean Net force on ball = ½(18 + 0)

Mean met force, F_m = 9N

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Thus;

½m(v_max)² = 0.405J

(v_max)² = 2 x 0.405/0.03

(v_max)² = 27

v(max) = √27

v_max = 5.2 m/s

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Describe at least four of the requirements (facts) that any model of solar system formation must include (according to the nebul
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Which graph below represents how the velocity of the sphere changes over time when falling with constant acceleration?
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Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.

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