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77julia77 [94]
3 years ago
12

A fortnite is an old English term that means 14 days. How many seconds are in a fortnite?

Physics
2 answers:
BartSMP [9]3 years ago
7 0

I assume you mean fortnight? haha

Anyway, to answer this question, we need to have prior knowledge of time measurements. You should know that there are 60 seconds in a minute, 60 minutes in an hour, and 24 hours in a day.

Therefore, if a fortnight is 14 days, we should multiply 14 by 24 to work out how many hours there are:

14 × 24 = 336 hours

Now, we should multiply 336 by 60 to work out the number of minutes:

336 × 60 = 20,160 minutes

And finally, we just need to multiply 20,160 by 60 again to work out the number of seconds:

20,160 × 60 = 1,209,600 seconds

And there you go! Your final answer is 1,209,600 seconds.

Andrew [12]3 years ago
3 0

Answer

1.21e+6

Explanation:

That is the way to properly write it

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Steam in a heating system flows through tubes whose outer diameter is 5 cm and whose walls are maintained at a temperature of 13
svet-max [94.6K]

Answer:

5945.27 W per meter of tube length.

Explanation:

Let's assume that:

  • Steady operations exist;
  • The heat transfer coefficient (h) is uniform over the entire fin surfaces;
  • Thermal conductivity (k) is constant;
  • Heat transfer by radiation is negligible.

First, let's calculate the heat transfer (Q) that occurs when there's no fin in the tubes. The heat will be transferred by convection, so let's use Newton's law of cooling:

Q = A*h*(Tb - T∞)

A is the area of the section of the tube,

A = π*D*L, where D is the diameter (5 cm = 0.05 m), and L is the length. The question wants the heat by length, thus, L= 1m.

A = π*0.05*1 = 0.1571 m²

Q = 0.1571*40*(130 - 25)

Q = 659.73 W

Now, when the fin is added, the heat will be transferred by the fin by convection, and between the fin and the tube by convection, thus:

Qfin = nf*Afin*h*(Tb - T∞)

Afin = 2π*(r2² - r1²) + 2π*r2*t

r2 is the outer radius of the fin (3 cm = 0.03 m), r1 is the radius difference of the fin and the tube ( 0.03 - 0.025 = 0.005 m), and t is the thickness ( 0.001 m).

Afin = 0.006 m²

Qfin = 0.97*0.006*40*(130 - 25)

Qfin = 24.44 W

The heat transferred at the space between the fin and the tube will be:

Qspace = Aspace*h*(Tb - T∞)

Aspace = π*D*S, where D is the tube diameter and S is the space between then,

Aspace = π*0.05*0.003 = 0.0005

Qspace = 0.0005*40*(130 - 25) = 1.98 W

The total heat is the sum of them multiplied by the total number of fins,

Qtotal = 250*(24.44 + 1.98) = 6605 W

So, the increase in heat is 6605 - 659.73 = 5945.27 W per meter of tube length.

5 0
3 years ago
n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Us
barxatty [35]

Answer:

The answer is "(1.265 \pm 0.010) \ s \ and \ 0.709 \%"

Explanation:

In point i:

T_{theo}= 2\pi \sqrt{\frac{l}{g}}

        =2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s

If  error in the theoretical time period :

\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2}  \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}

           = 0.010 \ s

 T_{theo} = (1.265 \pm 0.010) \ s

In point ii:

\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100

<h3>                     = \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%</h3>
5 0
3 years ago
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juin [17]

Answer:

ok i will no problem

Explanation:

6 0
3 years ago
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a student that just received their driver's license decides to buy a new car. he remembers from physics class that heat engines
blsea [12.9K]

Answer: the first law of thermodynamics

Explanation:

5 0
3 years ago
How much force is required to move a sled 5 meters if a person uses 60 J of work?
DerKrebs [107]
Force = work / dis
           = 60/ 5
           = 12 N
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3 years ago
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