Which energy is possessed by light bulb? kinetic or potential?

PLZ ANSWER WILL MARK BRAINLEST IF 2 PEOPLE ANSWER

yarga [219]

Answer:

B, yellow

Explanation:

yellow peas were dominant over the green peas, which were recessive

3 0

3 years ago

Read 2 more answers

An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a dist

mart [117]

Answer:

The final velocity, $v_{f}$ , is gd.

Explanation:

The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;

$v_{f}$ = $v_{i}$ + 2gs

where $v_{f}$ is the final velocity of the object, $v_{i}$ is the initial velocity of the object, g is the gravitational force and s is the height.

Since the object falls from a height of d, then $v_{i}$ = 0 m/s, and s = d.

So that;

$v_{f}$ = 0 + 2gd

= 2gd

$v_{f}$ = 2gd

When the distance is $\frac{d}{2}$ , $v_{i}$ = 0 m/s.

Then;

$v_{f}$ = 2g $\frac{d}{2}$

$v_{f}$ = g x d

When the object falls through the height $\frac{d}{2}$ , then the final velocity is gd.

4 0

3 years ago

What is the velocity of a beam of electrons that goes undeflected when passing through perpendicular electric and magnetic field

goldenfox [79]

F = qE + qV × B
where force F, electric field E, velocity V, and magnetic field B are vectors and the × operator is the vector cross product. If the electron remains undeflected, then F = 0 and E = -V × B
which means that |V| = |E| / |B| and the vectors must have the proper geometrical relationship. I therefore get
|V| = 8.8e3 / 3.7e-3
= 2.4e6 m/sec
Acceleration a = V²/r, where r is the radius of curvature.
a = F/m, where m is the mass of an electron,
so qVB/m = V²/r.
Solving for r yields
r = mV/qB
= 9.11e-31 kg * 2.37e6 m/sec / (1.60e-19 coul * 3.7e-3 T)
= 3.65e-3 m

6 0

3 years ago

The density of a rock is 2 g/mL and its’ been displaced in water with a volume of 25 mL. Calculate the mass of the rock in grams

Ludmilka [50]

Answer:

d =

m

V

m = d×V

V =

m

d

DENSITY

Density is defined as mass per unit volume.

d =

m

V

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =

m

V

=

433

g

200

c

m

³

= 2.16 g/cm³

MASS

d =

m

V

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×

1.11

g

1

m

L

= 555 g

VOLUME

d =

m

V

We can rearrange this to get the expression for the volume.

V =

m

d

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×

1000

g

1

k

g

= 14 830 g

Step 2: Calculate the volume.

V =

m

d

= 14 830 g ×

1

c

m

³

19.32

g

= 767.6 cm³

Explanation: got it from a site

4 0

4 years ago

In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward

Vladimir79 [104]

Answer:

The answer is " $1.01 \times 10^{-13}$ "

Explanation:

Using the law of conservation for energy. Equating the kinetic energy to the potential energy.

$KE=U=\frac{kqq'}{r}\\\\$

Calculating the closest distance:

$\to r=\frac{kqq'}{KE}\\\\$

$=\frac{k(2e)(79e)}{KE}\\\\=\frac{k(2)(79)e^2}{KE}\\\\=\frac{9.0\times 10^9 \ N \cdot \frac{m^2}{c}(2)(79)(1.6 \times10^{-19} \ C)^2}{(2.25\ meV) (\frac{1.6 \times 10^{-13} \ J}{1 \ MeV})}\\\\$

$=\frac{9.0\times 10^9 \times 2\times 79\times 1.6 \times10^{-19}\times 1.6 \times10^{-19} }{(2.25 \times 1.6 \times 10^{-13}) }\\\\=\frac{3,640.32\times 10^{-29}}{3.6 \times 10^{-13} }\\\\=\frac{3,640.32}{3.6} \times 10^{-16}\\\\=1011.2 \times 10^{-16}\\\\=1.01 \times 10^{-13}$

5 0

3 years ago

Which energy is possessed by light bulb? kinetic or potential?​

Which energy is possessed by light bulb? kinetic or potential?