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dimulka [17.4K]
3 years ago
15

Summarize why you need a partner for the Unit 4 lab. Your answer

Physics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

You need a partner in a lab, because in case you forgot something the teacher said, you can ask your partner. You can't always do everything by yourself, so if you have help next to you, they can help you so you won't struggle.

Explanation:

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9. How are ecological footprints useful?
Arte-miy333 [17]

As ecological footprints provide an easily communicable way of measuring the ecological bottom‐line condition for sustainability, it is a useful tool for promoting a sustainable future. It is particularly useful for cities, as it is in cities where the battle for sustainability will be won or lost.
6 0
3 years ago
Read 2 more answers
You tie the loose end of a 0.1 kg yo-yo string to your finger and then release the yo-yo so that it spins down toward the ground
Nikitich [7]

Answer:

The answer is "5.06 \times 10^{-6} \ kg \ m^2"

Explanation:

\to E_1=0..............(i)\\\\\to E_2= \frac{mV^2}{2} +\frac{Iw^2}{2} - mgh.............(ii)\\\\ \Delta E=0\\\\\to mgh= \frac{mV^2}{2} +\frac{Iw^2}{2} \\\\ \to 2 \ mgh=  mV^2 +Iw^2\\\\ \to 2 \ mgh- mV^2 =Iw^2\\\\ \to  m(2gh- V^2) =Iw^2\\\\ \to I= \frac{m(2gh- V^2)}{w^2}

       = 5.06 \times 10^{-6} \ kg \ m^2

3 0
3 years ago
0.002 written in scientific notation
Oliga [24]

Answer:0,002 = 2 x 10⁻³

Explanation:

0,002 = 2 / 1000 = 2 / 10³ = 2 x 10⁻³

3 0
3 years ago
A car with a velocity of 22 m/s is accelerated at a rate of 1.6m/s2 for 6.8s. determine the final velocity
Ivahew [28]

A car with a velocity of 22 m/s is accelerated at a rate of 1.6 m/s^2 for 6.8s has the final velocity t be 32.88 m/s.

The acceleration means the amount of velocity changing per unit time.

The given data:

initial velocity, u = 22 m/s

time, t = 6.8 s

acceleration, a = 1.6 m/s^2

We will be using the equation of motion:

v = u + at

\therefore v=22+1.(6.8)

\Rightarrow v=22+10.88

\Rightarrow v=32.88 \ m/s

The final velocity become 32.88 m/s.

To learn more about Attention here:

https://brainly.in/question/10557838

#SPJ4

3 0
2 years ago
Hey guys can y’all help quickly?
Naddik [55]

Answer:

Temporary? You have two options

If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).

If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).

Either way, the electron cloud will migrate towards the right side of the of your sphere.

Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.

7 0
2 years ago
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