Answer:
A) 1568.60 Hz
Explanation:
This change is frequency happens due to doppler effect
The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source
where
C = the propagation speed of waves in the medium;
Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;
Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.
A) Here the Source is moving towards the receiver(C-Vs)
and the receiver is standing still (Vr=0) therefore the observed frequency should get higher
12 is correct
Explanation: it's a cube
Answer:
The acceleration is 3.62 m/s²
Explanation:
Step 1: Data given
mass of the shell = 1.65 kg
angle = 38.0 °
Step 2: Calculate the acceleration
We have 2 forces working on the line of motion:
⇒ gravity down the slope = m*g*sinα
⇒ provides the linear acceleration
⇒ friction up the slope = F
⇒ provides the linear acceleration and also the torque about the CoM.
∑F = m*a = m*g*sin(α) - F
I*dω/dt = F*R
The spherical shell with mass m has moment of inertia I=2/3*m*R² Furthermore a pure rolling relates dω/dt and a through a = R dω/dt. So the two equations become
m*a = m*g sin(α) - F
2/3*m*a = F
IF we combine both:
m*a = m*g*sin(α) - 2/3*m*a
1.65a = 1.65*9.81 * sin(38.0) - 2/3 *1.65a
1.65a + 1.1a = 9.9654
2.75a = 9.9654
a = 3.62 m/s²
The acceleration is 3.62 m/s²
Answer:
V' = V/2
Explanation:
The voltage across a parallel plate capacitor is given as follows:
V = Q/C
where,
V = Voltage across capacitor
Q = Charge on Capacitor
C = Capacitance of Capacitor = A∈₀/d
Therefore,
V = Qd/A∈₀
where,
A = Area of plate
d = distance between plates
∈₀ = permittivity of free space
FOR CAPACITOR 1:
Q = Q
d = d
A = A
V = V
Therefore,
V = Qd/A∈₀ --------------- equation (1)
FOR CAPACITOR 2:
V' = ?
Q' = Q
d' = d
A' = 2A
Therefore,
V' = Q'd'/A'∈₀
V' = Qd/2A∈₀
V' = (1/2)(Qd/A∈₀)
using equation (1):
<u>V' = V/2</u>
