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When the life preserver is dropped from the helicopter, the only force acting on the object is the gravitational force. This modifies the equations of motion. Thus, the working equation is written below:
h = vt + 0.5gt²
where
v is the initial velocity
g is the acceleration due to gravity equal to 9.81 m/s²
h is the height of the fall
h = (1.46 m/s)(1.8 s) + 0.5(9.81 m/s²)(1.8 s)
h = 11.457 m
Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.
Explanation:
Mass of the astronaut on the moon , m= 72 kg
Acceleration due to gravity on moon,g = 1.63 
According to Newton second law of motion: F = ma
This will changes to = Weight = mass × g
The weight of a 72.0 kg astronaut on the Moon is 117.36 N.
<span>time of flight T = 4 sec
time to reach max height = 2 s
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if (u = 34 m/s) was initial speed and (p) angle of projection
u cos (p) *T = Horizontal Range
R = 4 u cos (p) ---------- (1)
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y = u sin (p) * t - 0.5 gt^2 ------- (2)
vy = speed vertical compo =dy/dt= u sin (p) - gt
vy =0 at max height
t (max) = 2 =given = u sin (p) /g
u sin (p) = 2g ------------------------------------ (3)
sin (p) = 2*9.8/34 = 0.5765
so > cos (p) = 0.8171
Range = R = 4 u cos (p) = 4*34*0.8171
R = 111.13 meter
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max height
y (max) = u sin (p) * 2 - 0.5 g*2^2
y (max) = 2g * 2 - 0.5 g*4
y (max) = 4g - 2g = 2g = 2*9.8 = 19.6 meter</span>
