Ask question

Ask question

All categories

2 years ago

14

What is the velocity of a beam of electrons that goes undeflected when passing through perpendicular electric and magnetic field

s of magnitude 8100 v/m and 6.0×10?3 t , respectively?

1 answer:

goldenfox [79]2 years ago

6 0

F = qE + qV × B
where force F, electric field E, velocity V, and magnetic field B are vectors and the × operator is the vector cross product. If the electron remains undeflected, then F = 0 and E = -V × B
which means that |V| = |E| / |B| and the vectors must have the proper geometrical relationship. I therefore get
|V| = 8.8e3 / 3.7e-3
= 2.4e6 m/sec
Acceleration a = V²/r, where r is the radius of curvature.
a = F/m, where m is the mass of an electron,
so qVB/m = V²/r.
Solving for r yields
r = mV/qB
= 9.11e-31 kg * 2.37e6 m/sec / (1.60e-19 coul * 3.7e-3 T)
= 3.65e-3 m

You might be interested in

Where should an object be placed in front of a concave mirror’s principal axis to form an image that is real, inverted, larger t

Charra [1.4K]

If the object is kept in between the principle axis and the focus but some what nearer to the focus then we will get the enlarge,erect,and real image.

7 0

3 years ago

Read 2 more answers

The atmosphere of Jupiter is essentially made up of hydrogen, H2. For H2, the specific gas constant is 4157 J/(kg K). The accele

Alenkinab [10]

Answer:

h=17357.9m

Explanation:

The atmospheric pressure is just related to the weight of an arbitrary column of gas in the atmosphere above a given area. So, if you are higher in the atmosphere less gass will be over you, which means you are bearing less gas and the pressure is less.

To calculate this, you need to use the barometric formula:

$P=P_0e^{-\frac{Mg}{RT}h}$

Where R is the gas constant, M the molar mass of the gas, g the acceleration of gravity, T the temperature and h the height.

Furthermore, the specific gas constant is defined by:

$R_{H_2}=\frac{R}{M}$

Therefore yo can write the barometric formula as:

$P=P_0e^{-\frac{g}{R_{H_2}T}h}$

at the surface of the planet (h =0) the pressure is $P_0[\tex]. The pressure at the height requested is half of that:[tex]P=\frac{P_0}{2}$

applying to the previuos equation:

$\frac{P_0}{2} =P_0e^{-\frac{g}{R_{H_2}T}h}$

solving for h:

h=17357.9m

3 0

3 years ago

Pulsars "blink" because they _____.

rosijanka [135]

A pulsar, or a pulsing star, is a highly magnetized neutron star that emits a beam of electromagnetic radiation. So they blink when they are rotating because the beam of radiation they emit can only be seen when it is facing the Earth.
Hope this helps.

4 0

2 years ago

In a vacuum, two particles have charges of q1 and q2, where q1 = +3.11 μC. They are separated by a distance of 0.241 m, and part

lesya [120]

Answer:

Charge of particle 2, $q_2=-7.13\ \mu C$

Explanation:

Given that,

Charge 1, $q_1=3.11\ \mu C=3.11\times 10^{-6}\ C$

The distance between charges, r = 0.241 m

Force experienced by particle 1, F = 3.44 N

We need to find the magnitude of electric charge 2. It can be calculated using formula of electrostatic force. It is given by :

$F=k\dfrac{q_1q_2}{r^2}$

$q_2=\dfrac{Fr^2}{kq_1}$

$q_2=\dfrac{3.44\times (0.241)^2}{9\times 10^9\times 3.11\times 10^{-6}}$

$q_2=7.13\times 10^{-6}\ C$

or

$q_2=7.13\ \mu C$

So, the magnitude of electric charge 2 is $q_2=7.13\ \mu C$ . Since, the force is attractive then the magnitude of charge 2 must be negative.

5 0

3 years ago

The route followed by a hiker consists of three displacement vectors A with arrow, B with arrow, and C with arrow. Vector A with

kotykmax [81]

Answer:

$D_{B}=1173.98m\\D_{C}=675.29m$

Explanation:

If we express all of the cordinates in their rectangular form we get:

A = (1404.77 , 655.06) m

$B = A + ( -D_{B} *sin(41) , -D_{B} * cos(41) )$

$C = A + B + ( -D_{C} *cos(20) , D_{C} * sin(20) )$

Since we need C to be (0,0) we stablish that:

$C = (0,0) = A + B + ( -D_{C} *cos(20) , D_{C} * sin(20) )$

That way we make an equation system from both X and Y coordinates:

$A_{x} + B_{x} + C_{x} = 0$

$A_{y} + B_{y} + C_{y} = 0$

Replacing values:

$1404.77 - D_{B}*sin(41) - D_{C}*cos(20) = 0$

$655.06 - D_{B}*cos(41) + D_{C}*sin(20) = 0$

With this system we can solve for both Db and Dc and get the answers to the question:

$D_{B}=1173.98m$

$D_{C}=675.29m$

7 0

3 years ago