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Viefleur [7K]
3 years ago
12

What is the differences between amorphous solid and crystalline solid​

Chemistry
1 answer:
sp2606 [1]3 years ago
6 0

Answer:

Crystalline solids have well-defined edges and faces, diffract x-rays, and tend to have sharp melting points.

 In contrast, amorphous solids have irregular or curved surfaces, do not give well-resolved x-ray diffraction patterns, and melt over a wide range of temperatures.

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What is the Representative<br> Particles in 1.00 mol <br> of atomic nitrogen
docker41 [41]

Answer:

a molecule.

Explanation:

5 0
2 years ago
What is the procedure used to separate nitrogen from the mixture of nitrogen and oxygen​
ankoles [38]

Answer:

Cryogenic distillation

Explanation:

Cryogenic Distillation is the process in which Nitrogen and Oxygen are separated from air. Thus in cryogenic distillations the components having very low boiling points are distilled selectively at low temperatures. This method produces products of high purity but also it is quite energy intensive.

8 0
3 years ago
Help mee, thank you. Science. Due tonight and I am very tired now :/
madreJ [45]
The first question it would would release the same amount.the answer to the second question would be the experimental group.
3 0
3 years ago
How many oxygen atoms are present in 23.6 grams of aspartame?
olga55 [171]
The formula of aspartame is <span>C14H18N2O5.
From the periodic table:
molecular mass of hydrogen = 1 grams
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of oxygen = 16 grams

This means that:
molar mass of aspartame = 14(12)+18(1)+2(14)+5(16) = 294 grams
Therefore, each 294 grams of aspartame contains 5(16) = 80 grams of oxygen. To know number of grams of oxygen in 23.6 grams of aspartame, simply use cross multiplication as follows:
mass of oxygen = (23.6x80) / 294 = 6.42 grams</span>
7 0
3 years ago
If 16.8 mL of the analyte H2C2O4 (oxalic acid) is titrated with 0.501 M KOH to 13.54 mL, determine the mass of the analyte.​
Neko [114]

Answer:

Mass of Analyte H2C2O4 = 18.18 grams

Explanation:

The balanced equation is:

H_{2}C_{2}O_{4}+2KOH\rightarrow K_{2}C_{2})_{4}+H_{2}O

The Molarity of Oxalic acid needed can be determined using:M_{1}V_{1}=M_{2}V_{2}

Here M1 = Molarity of Oxalic acid

V1 = Volume of oxalic acid

M2 = Molarity of KOH and V2 = Volume of KOH

M1 = ? , V1 = 16.8 mL , M2 = 0.501 M   ,  V2 = 13.54 mL

Put the values and solve for M2,

M_{1}V_{1}=M_{2}V_{2}

2\times M_{1}(16.8)=0.501\times 13.54

We are multiplying by 2 because , 1 H2C2O4 needs 2 KOH

M_{1}=\frac{0.501\times 13.54}{2\times 16.8}

M_{1}=0.202M

Hence Molarity of H2C2O4 =

0.202 M

Molar mass = H2C2O4 = 2x1 +2x12 + 4x16

= 2+24+64 =  90 gram

Mole =molarity\times Molar\ mass

Moles=0.202\times 90

18.18 gram

8 0
3 years ago
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