Answer:
71.372 g or 0.7 moles
Explanation:
We are given;
- Moles of Aluminium is 1.40 mol
- Moles of Oxygen 1.35 mol
We are required to determine the theoretical yield of Aluminium oxide
The equation for the reaction between Aluminium and Oxygen is given by;
4Al(s) + 3O₂(g) → 2Al₂O₃(s)
From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.
Therefore;
1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen
1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium
Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.
4 moles of aluminium reacts to generate 2 moles aluminium oxide.
Therefore;
Mole ratio Al : Al₂O₃ is 4 : 2
Thus;
Moles of Al₂O₃ = Moles of Al × 0.5
= 1.4 moles × 0.5
= 0.7 moles
But; 1 mole of Al₂O₃ = 101.96 g/mol
Thus;
Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol
= 71.372 g
Answer:
9.63 Km is the equivalent to 9,630 m.
9.63 Km is the equivalent to 9,630 m. TRUE
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Answer:
A conclusion based upon reasoning
Explanation: if it is snowing outside, it is reasonable to infer that you need a coat.
Answer:
Hydrogen (H₂) gas at the cathode and Bromine (Br₂) gas at the anode
Explanation:
Bromine gas is evolved at anode.Since bromide ion is negatively charged it will go to anode to be oxidized and lose electrons.
while, Hydrogen gas is evolved at cathode .Since hydrogen ion is positively charged it will go to cathode reduced and gain electrons.
