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Mekhanik [1.2K]
3 years ago
10

Determine el número de muléculas y átomos contenidos en 64g de O2

Chemistry
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

muy bien te felicitó :) .

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On the basis of the expected charges on the monatomic ions, give the chemical formula of each of the following compounds: (a) ma
lakkis [162]

Answer:

(a) magnesium arsenide: As₂Mg₃

(b) indium(III) sulfide: In₂S₃

(c) aluminum hydride: AlH₃

(d) hydrogen telluride: H₂Te

(e) bismuth(III) fluoride: BiF₃

Explanation:

(a) magnesium arsenide:

The expected oxidation states are-

Magnesium ion- Mg²⁺

Arsenide ion- As³⁻

The chemical formula is: As₂Mg₃

(b) indium(III) sulfide:

The expected oxidation states are-

Indium ion- In³⁺

Sulfide ion- S²⁻

The chemical formula is: In₂S₃

(c) aluminum hydride:

The expected oxidation states are-

Aluminium ion- Al³⁺

Hydride ion- H⁻

The chemical formula is: AlH₃

(d) hydrogen telluride:

The expected oxidation states are-

Hydrogen - H⁺

telluride ion- Te²⁻

The chemical formula is: H₂Te

(e) bismuth(III) fluoride:

The expected oxidation states are-

bismuth ion- Bi³⁺

fluoride ion- F⁻

The chemical formula is: BiF₃

5 0
3 years ago
If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
GaryK [48]
<span>First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet
       
And the total number of snow flakes per minute on the entire lawn is:
   
(1350 snowflakes per minute per square foot) x (420 square feet) = 567,000 snowflakes per minute
       
In one hour (or 60 minutes) we get a total of:
   
(567,000 snowflakes per minute) x (60 minutes / 1 hour) = 34,020,000 snowflakes
       
The total mass of which would be:
   
34,020,000 snowflakes x 1.60 mg = 54,432,000 mg = 54.432 kg (as 1 kg = 1,000,000 mg).
       
So 54.432 kg of snow accumulates every hour on the lawn.</span>
7 0
3 years ago
How much heat is needed to melt 10.0 grams of ice at -10°C until it is water at 10°C?
zhannawk [14.2K]

The heat needed to melt 10.0 grams of ice at -10°C until it is water at 10°C is 3,969.5 J. (approx= 3963J).

<h3>What is Sensible heat? </h3><h3 />

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state.

Q= c×m×∆T

<h3>What is Latent heat? </h3><h3 />

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In this case, the heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q= m×L

Where,

L is the latent heat

<h3>-10°C to 0 °C</h3><h3 />

C= specific heat capacity of ice= 2.108 J/gK

M= 10 g

ΔT= T(final)– T(initial) = 0 °C – (-10 °C)= 10 °C= 10 K

Sensitive heat Q(1) = 2.108×10×10

= 210.8J

<h3>Heat needed to melt ice</h3><h3 />

The specific heat of melting of ice is 334 J/g, the heat needed to melt 10 grams of ice is

Q(2) = 10× 334

= 3340J

<h3>0°C to 10 °C</h3><h3 />

C= specific heat capacity of liquid water is 4.187 J/gK

M= 10 g

ΔT= T(final) – T(initial) = 10 °C – 0 °C= 10 °C= 10 K because being a temperature difference, the difference is the same in °C and K.

Q(3) = 4.187×10×10

= 418.7 J.

Total heat required= Q1 + Q2 + Q3

Total heat required= 210.8 J + 3,340 J + 418.7 J

= 3969.5J

Thus, the heat needed to melt 10 gram of ice from temperature-10°C to 10°C is 3969.5. Therefore, option B is correct option.

learn more about heat :

brainly.com/question/16818736

#SPJ1

8 0
2 years ago
Which two layers are part of the thermosphere?
borishaifa [10]

Answer:

exosphere and ionosphere.

Explanation:

very high up,the earth's atmosphere becomes very thin. the region where atoms and moleculesescape into space is referred to as the exosphere. exosphere is on top of the thermosphere.

scientists what is called the ionospherean extension of the thermosphere. so technically, ionosphere is not another atmospheric layer.

6 0
3 years ago
Read 2 more answers
What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


4 0
3 years ago
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