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Llana [10]
3 years ago
13

The specific heat of copper metal is 0.385 J/(g × °C). How much energy must be added to a 35.0 gram sample of copper to change t

he temperature from 20.0°C to 65.0°C? (2 points)
270 J
809 J
606 J
1130 J
Chemistry
1 answer:
Montano1993 [528]3 years ago
3 0
Q = mC∆T 

<span>where: </span>
<span>q = heat </span>
<span>m = mass of substance = 35.0 grams </span>
<span>C = 0.385 J/g*C </span>
<span>∆T = change in temperature = 65C - 20C = 45C </span>

<span>q = (35.0 g)*(0.385 J/g*C)*(45C) = 606 J </span>
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When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati
babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}

Here, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 1
  • Cl = 1

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 1
  • H = 2
  • Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply H_{2}O by 2 on product side. Therefore, the equation can be rewritten as follows.

MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}

Hence, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

6 0
3 years ago
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
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Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

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Answer:

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Explanation:

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The reaction in which methane is burned, CH4 +202 --&gt; 2H20 + CO2, is an example of a
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Answer: Combustion

Explanation:

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Answer:

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3 years ago
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