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3 years ago

. mc076-1.jpg If mc076-2.jpg and mc076-3.jpg, what is mc076-4.jpg?

1 answer:

3 0

.JPG is a format of any picture on the digital source. mc076 is could be a file of any picture. Well there is no more detail in the question that what kind of this file but it can 100 % right that these files are belong from any Picture.

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Melinda has shown that a function, f(x), increases by 4 for every unit in the domain. What does this prove?

inn [45]

It proves The function f(x) is an arithmetic sequence.

5 0

3 years ago

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Equivalent fractions

mestny [16]

Well, 6/8 can be simplified: divide the numerator and denominator by 2, then your simplified fraction is 3/4. Now, multiply straight across: 4 times what=12? 3 does. So, you do the same thing to the numerator, because whatever you do to the denominator must be done to the numerator, and same reversed. 3*3=9, so the answer to this is 9/12!!

6 0

3 years ago

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150 - x = 87 what does x equal here ?

Ainat [17]

Answer:

x=63

Step-by-step explanation:

Subtract by 150 from both sides of equation.

150-x-150=87-150

Simplify.

87-150=-63

-x=-63

Divide by -1 from both sides of equation.

-x/1=-63/-1

Simplify, to find the answer.

-63/-1=63

x=63 is the correct answer.

I hope this helps you, and have a wonderful day!

5 0

3 years ago

Read 2 more answers

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

3 years ago

Mary bought these art supplies: 4 paint brushes @ $1.29 each, 6 dowel rods @ $1.49 each, a jar of paste @ $1.25, and 2 canvases

Sophie [7]

Answer:

Option (1) is correct

The amount she receives back from $40 is $12.65

Step-by-step explanation:

Given: Mary bought the art supplies.

4 paint brushes @ $1.29 each, 6 dowel rods @ $1.49 each, a jar of paste @ $1.25, and 2 canvases @ $6.00 each.

We have to find the change she get from $40.

We first find the total cost of the art supplies.

Since, she brought 4 paint brushes @ $1.29 each,

Thus, cost of 4 paint brush is 1.29 × 4 = $5.16

Also, 6 dowel rods @ $1.49 each,

Thus, cost of 6 dowel rods is 1.49 × 6 = $8.94

Thus, cost of 1 jar of paste is $1.25

and 2 canvases @ $6.00 each

Thus, cost of 2 canvases is $12.00

Thus, total cost of art supplies = 5.16 + 8.94 + 1.25 + 12 =$27.35

Thus, amount she receives back from $40 is $40 - $12.35 = $12.65

4 0

3 years ago

Read 2 more answers