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denpristay [2]
3 years ago
10

1.An 8-kilogram bowling ball is rolling in a straight line toward you. If its momentum is 16 kg•m/s, how fast is it traveling?

Physics
1 answer:
Lilit [14]3 years ago
4 0
1. An 8-kilogram bowling ball is rolling in a straight line toward you. If its momentum is 16 kg•m/s, how fast is it traveling?
 
momentum = mass x velocity
16 = 8 x velocity
velocity = 2 m/s

2.A beach ball is rolling in a straight line toward you at a speed of 0.5 m/sec. Its momentum is 0.25 kg•m/s. What is the mass of the beach ball?

momentum = mass x velocity
0.25 = m x 0.5
mass = 0.5 kg

3.A 4,000-kilogram truck travels in a straight line at 10.0 m/s. What is its momentum?
Momentum = (mass) x (speed) = (4,000) x (10) = 40,000 kilogram-meters/second

4.A 1,400-kilogram car is also traveling in a straight line. Its momentum is equal to that of the truck in the previous question. What is the velocity of the car?

40,000 kilogram-meters/second = 1400 x velocity
velocity = 28.6 m/s

5.Which would take more force to stop in 10 seconds: an 8.0-kilogram ball rolling in a straight line at a speed of 0.2 m/s or a 4.0-kilogram ball rolling along the same path at a speed of 1.0 m/s?

F1 = 8 x  0.2 / 10 = 0.16 N
F2 = 4 x 1.0 / 10 = 0.4 N ----> take more force

6.The momentum of a car traveling in a straight line at 20 m/s is 24,500 kg•m/s. What is the car’s mass?

24500 = mass x 20
mass = 1225 kg

7.Another pitcher throws the same baseball in a straight line. Its momentum is 2.1 kg•m/s. What is the velocity of the ball?

2.1 = 0.5 x velocity
velocity = 4.2 m/s

8 A 1-kilogram turtle crawls in a straight line at a speed of 0.01 m/s. What is the turtle’s momentum?

momentum = 1 x 0.01 = 0.01 kg m/s
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Drag the tiles to the correct boxes to complete the pairs.
marishachu [46]

Answer:

Air pollution---> smog

Water pollution---> eutrophication

Land pollution---> contaminated soil

Light pollution---> sky glow

7 0
3 years ago
A scientist directs monochromatic light toward a single slit in an opaque barrier. The light has a wavelength of 580 nm and the
vredina [299]

Answer:

a) 9.72 mm

b) 4.86 mm

Explanation:

wave length of light  λ is  580 nm = 580 \times 10⁻⁹ m

Width of slit d = 0.215\times 10⁻³ m

Distance of screen D  = 1.8 m.

Width of one fringe = \frac{\lambda\times D}{d}

Putting the values we get fringe width

= \frac{580\times10^{-9}\times1.8}{.000315}

=4.86 mm.

a) Width of central maxima = 2 times width of one fringe

= 2 times 4.86

=9.72 mm

b) width of each fringe except central fringe  is same , no matter what the order is.Only brightness changes .

So width of either of the two first order bright fringe will be same and it will be  

= 4.86 mm.

3 0
3 years ago
The density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as meas
alexgriva [62]

Answer:

B.  inverse plot, 0.51 kilograms/meter3

Explanation:

First of all, we note that the relationship between the altitude and the atmospheric density is an inverse relationship. In fact, an inverse relationship is a relationship between the x-variable and the y-variable of the form

y \propto \frac{1}{x}

Therefore, as the x increases, the y decreases, and as the x decreases, they increases. This is exactly what occurs with the altitude and the atmospheric density in this plot: as the altitude increases, the density decreases, and vice-versa.

Moreover, we can infer the value of the atmospheric density at an altitude of 1,291 km. This point is located between point A (2550 km) and point B(1000 km), so the density must have a value between 0.30 kg/m^3 and 0.54 kg/m^3, so the correct choice is

B.  inverse plot, 0.51 kilograms/meter3


5 0
3 years ago
A sample of oxygen gas at 25.0°c has its pressure tripled while its volume is halved. What is the final temperature of the gas?
Marat540 [252]

Answer:

447 K

Explanation:

25 C = 25 + 273 = 298 K

Assuming ideal gas, we can apply the ideal gas law

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

T_2 = T_1\frac{P_2}{P_1}\frac{V_2}{V_1}

Since pressure is tripled, then P_2 / P_1 = 3. Volume is halved, then V_2 / V_1 = 0.5

T_2 = 298*3*0.5 = 447 K

4 0
3 years ago
Read 2 more answers
You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30°C to
earnstyle [38]

The correct answer to the question is : D) 352.6 m/s.

CALCULATION :

As per the question, the temperature is increased from 30 degree celsius to 36 degree celsius.

We are asked to calculate the velocity of sound at 36 degree celsius.

Velocity of sound is dependent on temperature. More is the temperature, more is velocity of sound.

The velocity at this temperature is calculated as -

                            V = 331  + 0.6T m/s

                               = 331 + 0.6 × 36 m/s

                               = 331 + 21.6 m/s

                               = 352.6 m/s.

Here, T denotes the temperature of the surrounding.

Hence, velocity of the sound will be 352.6 m/s.

5 0
3 years ago
Read 2 more answers
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