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bezimeni [28]
1 year ago
9

Pls solve this numerical.​

Physics
1 answer:
harkovskaia [24]1 year ago
4 0

Answer:

You should write the vectors in their proper sequence: i , j, k

If the vectors are perpendicular their dot product must be zero:

1) A dot B   is obviously zero since A and B have no common terms in i , j , k

2) looks like A = 2 i - 4 j + 3 k and B = i + 2 j + 2 k

A dot B = (2 * 1) + (-4 * 2) + (3 * 2) = 0

Note that the dot product produces a scalar with no direction (vector components)

Only i dot i, j dot j, and k dot k    have components   i dot j = zero, etc.

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Which compound has ionic bonding? A. Cl2 B. HF C. CaO D. NO2
GrogVix [38]

the answer is CaO because that's what my homework says is correct


7 0
3 years ago
How does a savanna differ from a grassland?
Pepsi [2]

Answer:

B. Savannas have shrubs and isolated trees, while grasslands contain grasses.

8 0
3 years ago
Read 2 more answers
A shot-putter projects the shot at 42.00˚ to the horizontal from a height of 2.100 m. It lands 17.00 m away horizontally. Next,
Tamiku [17]

Answer:

Explanation:

Let 100 m/s  be the velocity of projection.

So horizontal component

= 100 cos42

= 74.31 m /s

Vertical component = - 100 sin 42 . in upward direction

66.91 m/s

Net displacement = 2.1 downwards ( + ve )

Using s = ut + 1/2 gt²

2.1 = - 66.91 t  + .5 x 9.8 x t²

4.9 t² -  66.91 t - 2.1 = 0

t = 13.685 s

Horizontal distance covered

= 13.685 x 74.31

= 1016.93 m

If angle of projction is 40°

So horizontal component

= 100 cos40

= 76.60 m /s

Vertical component = - 100 sin 42 . in upward direction

64.27 m/s

Net displacement = 2.1 downwards ( + ve )

Using s = ut + 1/2 gt²

2.1 = -76.60 t  + .5 x 9.8 x t²

4.9 t² -  76.60 t - 2.1 = 0

t = 15.659  s

Horizontal distance covered

= 15.659 x 76.60

= 1199.49  m

So horizontal range is increased , if angle of projection is increased .

8 0
3 years ago
The coil springs on a car's suspension have a value of k = 64000 N/m. When the
AlladinOne [14]

80 joule is momentarily stored in each spring

<em><u>Solution:</u></em>

Given that,

The coil springs on a car's suspension have a value of k = 64000 N/m

When the  car strikes a bump the springs briefly compress by 5.0 cm (.05 m)

By compressing the spring, we apply a force over a distance

As a result we have done work on the spring

Doing work means that we have transferred energy to spring in form of elastic potential

Therefore,

k = 64000 N/m

x = 0.05m

<em><u>The elastic potential energy is given as:</u></em>

PE = \frac{1}{2}kx^2

Where, "k" is the spring constant and "x" is the displacement

PE = \frac{1}{2} \times 64000 \times 0.05^2\\\\PE = 32000 \times 0.0025\\\\PE = 80

Thus 80 joule is momentarily stored in each spring

8 0
3 years ago
Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with
Mekhanik [1.2K]

Answer: 0.013 seconds

Explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds

8 0
3 years ago
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