Answer: k = ma + uk×mgcosθ/ xf
Explanation: The body is placed on a frictionless inclined ramp.
The weight of the object has 2 components, horizontal component (mgsinθ) and vertical component (mgcosθ).
The horizontal component of weight is responsible for making tje object slide down the plane even with no applied force.
So from newton's second law of motion
mgsinθ - uk×R = ma
Where uk = coefficient of kinetic friction.
R = normal reaction = mgcosθ
mgsinθ - uk×mgcosθ = ma
mgsinθ = ma + uk×mgcosθ
mgsinθ is the applied force in this case. This applied force compresses a spring.
According to hooke's law,
F =ke
Where F = ma + uk×mgcosθ, e =xf
F = applied force , e = extension and k = spring constant.
k = F/e
k = ma + uk×mgcosθ/ xf
Answer:
3 laws of planetary motion
Answer:
C) С
Explanation:
'C' and 'E' are compressions.
'A' and 'D' are rarefactions.
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The purpose or how it orbits
The purpose is for future missions into space such as the moon, mars, or asteroids
It’s orbits due to being in low orbit of earth
Answer:
A book on its side exerts a greater force.
Explanation:
Pressure = Force / Area
Assuming that 1kg = 10N
2kg = 20N
Area of book lying flat = 0.3m × 0.2m
= 0.6m²
Pressure of book lying flat = 20N / 0.6m²
= 30Pa (1 s.f.)
Area of book on its side = 0.2m × 0.05m
= 0.01m²
Pressure of book on its side = 20N / 0.01m²
= 2000Pa (1 s.f.)
Since 2000Pa (1 s.f.) > 30Pa (1 s.f.), a book on its side applies greater pressure than lying flat.