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3 years ago

A diesel truck produces 47.5kJ of useful output energy from 125kJ of diesel fuel.what is the truck efficiency?.show the solution

Chemistry

1 answer:

Alex Ar [27]3 years ago

7 0

You have to do a report :
$\frac{E_f}{E_i} = \frac{47,5}{125} = 0,38$

So the truck efficiency is 38%.

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The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

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The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

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Thus the high value of K indicates that $CN^-$ is a stronger base than $ONO^-$

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