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olganol [36]
2 years ago
14

NaHCO3 is an example of -

Chemistry
1 answer:
bezimeni [28]2 years ago
8 0

Answer:

sodium bicarbonate

Explanation:

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Explain how interactions can be both beneficial and harmful to the organism in a community
Marysya12 [62]
Interactions to an organism can be both harmful and beneficial due to the organism's circumstances. For example by adding tadpoles to an eco system it results in the tadpoles eating all the food thus killing the other organisms. Whereas by adding plants to an ecosystem it provides shelter for the organisms and possibly food being beneficial.
7 0
3 years ago
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¿Cuántos moles de C3H8 contienen 9.25 x 10^24 moléculas?
Igoryamba

Answer:

\large \boxed{\text{e. 15.4 mol C$_{3}$H}_{8}}

Explanation:\text{Moles of propane} = 9.25 \times 10^{24}\text{ molecules} \times \dfrac{\text{1 mol }}{6.022 \times\ 10^{23} \text{molecules}} = \textbf{15.4 mol}

5 0
3 years ago
Quarks are<br> A A Fact<br> B Fiction<br> C Both of the above<br> D Neither of the above
stiks02 [169]
I’d say A. They are theoretical in the fact that they have not been observed directly, but have been confirmed to exist through experimentation.
7 0
2 years ago
A cool, yellow-orange flame is used to heat the crucible. Would this affect the mass of the crucible? If so, how?
s2008m [1.1K]

Answer:

yes

Explanation:

Usually, it would not affect the crucible, but depending on the temperature of the flame the enamel of the crucible may begin to melt and stick to the metal object being used to handle the crucible. This tiny amount that is melted off can cause very small changes in the original mass of the crucible, which although it is almost unnoticeable it is still there. Therefore, the answer to this question would be yes.

5 0
3 years ago
How many liters of chlorine gas can react with 56.0 grams of calcium metal at standard temperature and pressure? Show all of the
Doss [256]
The balanced chemical reaction is:

<span>Ca + Cl2 =  CaCl2
</span>
We are given the amount of calcium metal to be used for this reaction. This will be the starting point for the calculations.

56 g Ca ( 1 mol Ca / 40.08 g Ca) (1 mol Cl2 / 1 mol Ca) ( 22.414 L Cl2 / 1 mol Cl2 ) = 31.32 L Cl2 gas produced from the reaction
5 0
3 years ago
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