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Verizon [17]
3 years ago
13

According to the principal of wave refraction, when light from the atmosphere enters a medium of greater density at an oblique a

ngle its _____________. a. velocity speeds up but angle remains the same b. velocity remains the same but angle changes c. velocity slows down but angle remains the same d. velocity slows down and angle changes
Physics
1 answer:
Hoochie [10]3 years ago
6 0

Answer:

d. velocity slows down and angle changes

Explanation:

You might be interested in
. A 6 ohm resistor is connected to a 15 volt battery.
Sunny_sXe [5.5K]

Answer:

2.5A , 22500 JOULE

Explanation:

Resistance (R)= 6 ohm

Voltage (V) = 15 volt

a)

Current (I) = ?

From ohm's law,

V=IR

15 = 6*I

I = 2.5 A

b)

time(t) = 10min = 600 second

heat energy (Q) = ?

from Joule's law of heating,

Q = I²*R*t

Q = 2.5² *6*600

Q = 22500 Joule

hence, heat energy produced is 22500 joule.

3 0
2 years ago
The gravitational force between two volleyball players is 3.9 × 10^-7 N . If the kasses of the players are 63 kg and 78 kg, what
N76 [4]

Answer:

I honestly have no idea bro.

Explanation:

Hope that helps have a great night.

3 0
2 years ago
Malik formed a hypothesis that an increase in atmospheric oxygen levels by 10% would cause red-legged grasshoppers to grow large
worty [1.4K]
<h2>Answer:</h2>

The option C is the correct answer.

Which is, "He varies the nitrogen and carbon dioxide levels in the air from one trial to the next".

<h3>Explanation:</h3>

The hypothesis of Malik was about the effect of increased oxygen level on the growth of the red-legged grasshoppers.

So the areas of his experiment should be the:

  • Grasshopper type.
  • High oxygen level.
  • Rate of growth of grasshopper.

So all the given options are relevant to his experiment except the third one.

So varying the nitrogen and carbon dioxide level in air could not contribute in his experiment.

<h2 />
8 0
3 years ago
Read 2 more answers
What is the frequency of an X-ray with wavelength 0.13 nm ? Assume that the wave travels in free space. Express your answer to t
dem82 [27]

Answer:

Frequency, f=2.30\times 10^{18}\ Hz

Explanation:

Given that,

The wavelength of the x-rays, \lambda=0.13\ nm=0.13\times 10^{-9}\ m

We need to find the frequency of an x-ray. All electromagnetic wave travel with a speed of light. It is given by the formula as :

c=f\lambda

f is the frequency

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.13\times 10^{-9}}\\\\f=2.30\times 10^{18}\ Hz

So, the frequency of an x-ray is 2.30\times 10^{18}\ Hz. Hence, this is the required solution.

5 0
3 years ago
Only one of three balls A, B, and C carries a net charge q. The balls are made from conducting material and are identical. One o
Zarrin [17]

Answer:

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

Explanation:

The metals distribute the charge on all surface when they touch the surface increases so that charge density decreases and when the charge is separated into smaller in each metal.

Let's apply this principle to our case.

One of the spheres is loaded with a charge q, when touching a ball its charge is reduced to 1 / 2q for each ball.

         qA = ½ q

         qB = ½ q

         qC = 0

The total charge is q

we make a second contact

If we touch the ball A again with the other sphere not charged C, the chare is distributed and when separated it is reduced by half

         qA = 1/2 (q / 2) = ¼ q

         qC = ¼ q

         qB = ½ q

At this point all spheres have a charge,

      qA = ¼ q

      qb = ½ q

      qC = ¼ q

The total charge is q

Now let's contact spheres B and one of the other two

       Q = ½ q + ¼ q = ¾ q

When splitting the charge

        qB = ½ ¾ q = 3/8 q

        qC = ½ ¾ q = 3/8 q

        qA = ¼ q

The total charge is q

Note that the total load is always equal to q

Now let's analyze the given configuration

Let's look for the total load

       Q = qA + QB + QC

       Q = ½ q + 3/8 q + ¼ q

        Q = 9/8 q

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

8 0
3 years ago
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