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Alenkinab [10]
3 years ago
10

Consider the following equilibrium. 2 SO2 (g) + O2 (g) 2 SO3 (g) The equilibrium cannot be established when ________ is/are plac

ed in a 1.0-L container.
Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

Question is incomplete, the complete question is pasted below.

Consider the following equilibrium. 2SO2(g) + O2(g) ⇌2SO3(g) The equilibrium cannot be established when ________ is/are placed in a 1.0-L container?

A) 0.50 mol O2 (g) and 0.50 mol SO3 (g)

B) 1.0 mol SO3 (g)

C) 0.25 mol SO2 (g) and 0.25 mol O2 (g)

D) 0.75 mol SO2 (g)

E) 0.25 mol of SO2 (g) and 0.25 mol of SO3 (g)

Answer:

The correct answer is : D) 0.75 mol SO2 (g)

Explanation:

Option A is not true because both SO3 can be converted into SO2 and O2 and equilibrium can be achieved.

Option B is not true because SO3 will be decomposed into SO2 and O2 and can achieve equilibrium.

Option C is not true because both SO2 and O2 will react and make SO3 and can achieve equilibrium.

Option D is correct because SO2 requires O2 to react and form SO3. Since O2 is not present, thus reaction will not occur and equilibrium will not be achieved.

Option E is not true because SO3 can decompose into O2 and SO2 and can achieve equilibrium.

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Given that ΔH = −571.6 kJ/mol for the reaction 2 H2(g) + O2(g) → 2 H2O(l), calculate ΔH for these reactions. (a) 2 H2O(l) → 2 H2
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Answer : The value of \Delta H for the reaction is +571.6 kJ/mole.

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2(g)+O_2(g)\rightarrow 2H_2O(l)     \Delta H_1=-571.6kJ/mole

Now we have to determine the value of \Delta H for the following reaction i.e,

2H_2O(l)\rightarrow 2H_2(g)+O_2(g)    \Delta H_2=?

According to the Hess’s law, if we reverse the reaction then the sign of \Delta H change.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=-(-571.6kJ/mole)

\Delta H_2=+571.6kJ/mole

Hence, the value of \Delta H for the reaction is +571.6 kJ/mole.

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the rate of disappearance of Br- at some moment in time was determined to be 3.5 x 10-4 M/s. What is the rate of appearance of B
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Answer:

1.8 × 10⁻⁴ mol M/s

Explanation:

Step 1: Write the balanced reaction

2 Br⁻ ⇒ Br₂

Step 2: Establish the appropriate molar ratio

The molar ratio of Br⁻ to Br₂ is 2:1.

Step 3: Calculate the rate of appearance of Br₂

The rate of disappearance of Br⁻ at some moment in time was determined to be 3.5 × 10⁻⁴ M/s. The rate of appearance of Br₂ is:

3.5 × 10⁻⁴ mol Br⁻/L.s × (1 mol Br₂/2 mol Br⁻) = 1.8 × 10⁻⁴ mol Br₂/L.s

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