In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.
given that :
The solute in the solution by mass percent = 10 %
mass percent = ( mass of solute / mass of solution ) × 100%
mass of solute in the solution is = 10 g
The solvent present in solution by mass percent = 90 %
the mass of solvent in the solution is is 90 g
Thus, In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.
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True, Scientific theories may change with the addition of new information or improved experiments and observations.
Answer:
300K.
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 300L
Initial temperature (T1) = 200K
Final volume (V2) = 450L
Final temperature (T2) =..?
Since the pressure is constant, the gas is obeying Charles' law.
Using the Charles' law equation, we can obtain the new temperature of the gas as follow:
V1/T1 = V2/T2
300/200 = 450/T2
Cross multiply to express in linear form
300 x T2 = 200 x 450
Divide both side by 300
T2 = (200 x 450)/ 300
T2 = 300K
Therefore, the new temperature of the gas is 300K.
It doesn’t let me see the picture it’s blurry.
<span>C. A completely new substance is formed.</span>