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lora16 [44]
3 years ago
13

How does flowing water change the earths surface

Physics
1 answer:
Art [367]3 years ago
3 0
Deposition occurs when gravity's downward pull on sediment is greater than the push of flowing water<span> or wind. Rivers and streams erode soil, rock, and sediment. Sediment is tiny grains of broken-down rock.</span>
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A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
4 years ago
How long would it take me to travel 48 milllion miles at 200000 mph?
MakcuM [25]
For this question, you must divide 48 million by two hundred thousand to get your answer. The quotient of these number is 240, which if reduced to days, is exactly ten days.
5 0
3 years ago
What is the weight of an object that has a mass of 40kg
Nina [5.8K]

Answer:

The mass of the object would be 392. i hope this helps :)

Explanation:

4 0
3 years ago
100 POINTS. Help Please.
soldi70 [24.7K]

Answer:

The electrical force between two balloons is 67.5N.

Explanation:

There are two charged balloons, let's say a and b.

The charge on the balloon a = Q_a = 3.0 * 10^{-6}C

The charge on the balloon b = Q_b = 2.5 * 10^{-7}C

Both balloons are 1 cm apart; it means that the distance<em> r</em> between the balloon a and the balloon b is 0.01 m (since 1 cm = 0.01 m).

We need to find the electrical force between them. By using the Coulomb's law, the magnitude of the electrical force between both the balloon is given as follows:

F = \frac{kQ_aQ_b}{r^2} --- (A)

Where,

k = Coulomb's constant = \frac{1}{4\pi\epsilon_o} = 9 * 10^9 \frac{Nm^2}{C^2}

Plug all the values in the equation (A):

F = \frac{(9*10^9)(3.0*10^{-6})(2.5*10^{-7})}{(0.01)^2} \\F = 67.5 N

Hence, the electrical force between two balloons is 67.5N (three significant figures).

4 0
3 years ago
Read 2 more answers
4) A drag racer starts her car from rest and accelerates at 10.0 m/s² for a distance of 400 m (1/4 mile). (a) How long did it ta
mel-nik [20]

Answer:

A) s=1/2at^2

t=√(2s/a)=√(2x400)/10.0)=9.0s

B) v=at

v=10.0x9=90m/s

3 0
3 years ago
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