Answer:
Mirage is a phenomenon which can be seen when the surface air gets heated up and it becomes lighter. Lighter air moves up in the atmoshphere.
Explanation:
When the lighter air from cooler areas to warmer areas are refracted and they bent upwards.and it dispers
,
The three most normal units of estimation for temperature are Celsius, Fahrenheit, and Kelvin.
A thermometer is an instrument that measures temperature. It can gauge the temperature of a strong, for example, food, fluid like water, or gas like air.
The Celsius scale is important for the decimal measuring standard. The decimal standard of estimation additionally incorporates units of mass, like kilograms, and units of length, like kilometers. Most logical fields measure temperature utilizing the Celsius scale. Zero degrees Celsius is the edge of freezing over water, and 100 degrees Celsius is the limit of water. Three countries don't utilize the Celsius scale. The United States, Burma, and Liberia utilize the Fahrenheit scale to quantify temperature. In any case, even in these nations, researchers utilize the Celsius or kelvin scale to gauge temperature. Water freezes at 32 degrees Fahrenheit and bubbles at 212 degrees Fahrenheit. The Kelvin scale is utilized by physicists and different researchers who need to record exceptionally exact temperatures. The Kelvin scale is the main unit of estimation to incorporate the temperature for "outright zero," the complete shortfall of any intensity energy.
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If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, the volume is reduced to one-third of its original value. <em>(a)</em>
You can find velocity when acceleration is constant.
file example see below.
Answer: SG = 2.67
Specific gravity of the sand is 2.67
Explanation:
Specific gravity = density of material/density of water
Given;
Mass of sand m = 100g
Volume of sand = volume of water displaced
Vs = 537.5cm^3 - 500 cm^3
Vs = 37.5cm^3
Density of sand = m/Vs = 100g/37.5 cm^3
Ds = 2.67g/cm^3
Density of water Dw = 1.00 g/cm^3
Therefore, the specific gravity of sand is
SG = Ds/Dw
SG = (2.67g/cm^3)/(1.00g/cm^3)
SG = 2.67
Specific gravity of the sand is 2.67
