Answer:0 J
Explanation:
Given
For first step
change in internal Energy of the system is 
Work done on the system 
For second step
change in internal Energy of the system is 
Work done on the system 
Work done on the system is considered as Positive and vice-versa.
and from first law of thermodynamics

for first step


overall heat added
For overall Process Heat added is 0 J
Answer:

Explanation:
Let x be the distance to the shore
From trigonometry properties:

The acceleration formula goes like this: a= (vf-vi)/t so it would be (13-4)/3 Thus the answer is 3m/s^2
A distinct layer within a soil profile is called a soil horizon.