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3 years ago

14

What is the relationship between air temperature and humidity 10 pts

2 answers:

Brut [27]3 years ago

6 0

C.Warm air is usually more humid than cold air.

as the temperature increase, vapor pressure increase. this in turn decreases the humidity, hence the air can hold more water at high temperature.

goblinko [34]3 years ago

3 0

The answer is C. Warm air is usually more humid than cold air. Hope this helps.

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On a smooth horizontal floor an object

lukranit [14]

Answer:

what do you mean by this?

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3 years ago

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When Jim and Rob ride bicycles, Jim can only accelerate at three-quarters the acceleration of Rob. Both startfrom rest at the bo

Natali5045456 [20]

Answer:

46.4 s

Explanation:

5 minutes = 60 * 5 = 300 seconds

Let g = 9.8 m/s2. And $\theta$ be the slope of the road, s be the distance of the road, a be the acceleration generated by Rob, 3a/4 is the acceleration generated by Jim . Both of their motions are subjected to parallel component of the gravitational acceleration $gsin\theta$

Rob equation of motion can be modeled as s = a_Rt_R^2/2 = a300^2/2 = 45000a[/tex]

Jim equation of motion is $s = a_Jt_J^2/2 = (3a/4)t_J^2/2 = 3at_J^2/8$

As both of them cover the same distance

$45000a = 3at_J^2/8$

$t_J^2 = 45000*8/3 = 120000$

$t_J = \sqrt{120000} = 346.4 s$

So Jim should start 346.4 – 300 = 46.4 seconds earlier than Rob in other to reach the end at the same time

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4 years ago

Question 5 of 10

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3 years ago

what was the initial temperature is 250 calories reply .1 kg of gold the final temperature of the gold was 175°c ? the specific

weqwewe [10]

Answer:

$115.2^{\circ}C$

Explanation:

When an amount of energy Q is supplied to a substance of mass m, the temperature of the substance increases by $\Delta T$ , according to the equation

$Q=mC_s \Delta T$

where $C_s$ is the specific heat capacity of the substance.

In this problem, we have:

$Q=250 \cdot 4.184 =1046 J$ is the amount of heat supplied to the sample of gold

m = 0.1 kg = 100 g is the mass of the sample

$C_s = 0.175 J/gC$ is the specific heat capacity of gold

Solving for $\Delta T$ , we find the change in temperature

$\Delta T = \frac{Q}{m C_s}=\frac{1046}{(100)(0.175)}=59.8^{\circ}$

And since the final temperature was

$T_f = 175^{\circ}$

The initial temperature was

$T_i = T_f - \Delta T= 175 -59.8=115.2^{\circ}C$

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3 years ago

WHAT IS THE MASS OF AN OBJECT THAT WEIGHS 100 N?

Finger [1]

Answer:

10.2 kg

Explanation:

Assuming the object is on Earth:

w = mg

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