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2 years ago

8

What is the first 7 square numbers?

2 answers:

Pani-rosa [81]2 years ago

8 0

1, 4, 9, 16, 25, 36, and 49 because 1*1=1, 2*2=4, 3*3=9, 4*4=16, 5*5=25, 6*6=36, and 7*7=49

Degger [83]2 years ago

3 0

1 times 1 = 1
2 times 2 = 4
3 times 3 = 9
4 times 4 = 16
5 times 5 = 25
6 times 6 = 36
7 times 7 = 49
*Special info: If you subtract 4 - 1, 9 - 4, 16 - 9,....,you'll get 3, 5, 7, 9, 11, 13, 15 and it easier to do that, just add 49 to 15 and you get 64, 8 times 8 = 64.

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Use math vocabulary to explain why you think this number does not belong in the group. Be sure to write in complete sentences.

NISA [10]

Answer:

because like for example the given number are 01 12

23 34

or 12233445566778 and etc.

your situation are 4556 and 3224 because are not ordered pair

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2 years ago

Helppppppppppp meeeeeeeeeee

kozerog [31]

Answer:

It's 11.72

Step-by-step explanation:

Area=)1/2×15/4×25/4

Answer》11.72

Hope it helps...

Have a great day

3 0

2 years ago

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Find (fºg)(1)<br> f(x) = x² - 1<br> g(x) = √x <br> A.0<br> B.1<br> C.4 √2<br> D. √8

Savatey [412]

Given:

The function are

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

To find:

The value of $(f\circ g)(1)$ .

Solution:

We have,

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

We need to find the value of $(f\circ g)(1)$ .

$(f\circ g)(1)=f(g(1))$ $[\because (f\circ g)(x)=f(g(x))]$

$(f\circ g)(1)=f(\sqrt{1})$ $[\because g(x)=\sqrt{x}]$

$(f\circ g)(1)=f(1)$

$(f\circ g)(1)=(1)^2-1$ $[\because f(x)=x^2-1]$

$(f\circ g)(1)=1-1$

$(f\circ g)(1)=0$

The value of $(f\circ g)(1)$ is 0.

Therefore, the correct option is A.

4 0

2 years ago

ANYONE KNOW THIS NEED ASAP

Dmitry [639]

B, it’s the point that the lines cross

6 0

1 year ago

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Please help! Will give brainliest!<br> Simplify. <img src="https://tex.z-dn.net/?f=%283a%5E%7B2%7D%2A5a%5E%7B2%7D%29" id="TexFor

sergejj [24]

Answer: 8a

Step-by-step explanation:

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2 years ago

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