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AleksAgata [21]
4 years ago
6

When the shift occurs in the earth's crust , what does the energy radiates us out as ?

Chemistry
1 answer:
Stels [109]4 years ago
8 0
When a sudden break or shift occurs the energy radiates it comes out of the water
You might be interested in
A rectangular prism of volume 84 cm 3 has a mass of 760 g. What is the density of the rectangular prism? 5.8 g•cm 3 9.0 g/cm 3 6
Fiesta28 [93]

Answer:

9.0 g/cm³

Explanation:

Density can be computed with the formula:

D=\dfrac{M}{V}

Where:

D = Density

M = Mass

V = Volume

In your problem we are given:

84 cm³ = volume

760 g = mass

So we just plug in our given into the formula:

D=\dfrac{M}{V}

D=\dfrac{760g}{84cm^{3}}

D=9.05g/cm^{3}

The answer would then be:

9.0 g/cm³

3 0
4 years ago
Which is the correctly balanced chemical equation for the reaction of KOH and H2SO4? Which is the net ionic equation for the rea
NeX [460]

Answer:

See explanation

Explanation:

A balanced chemical reaction equation has the same number of atoms of each element on both sides of the reaction equation.

Hence, for the reaction between KOH and H2SO4, the balanced chemical reaction equation is;

H2SO4(aq) + 2KOH(aq) ---------> K2SO4(aq) + 2H2O(l)

Complete ionic equation;

2H^+(aq) + SO4^2-(aq) + 2K^+(aq) +2OH^-(aq) -------> SO4^2-(aq) + 2K^+(aq) + 2H2O(l)

Net ionic equation;

2H^+(aq) + 2OH^-(aq) -------> 2H2O(l)

6 0
3 years ago
What's the difference between a molecular formula and a structural formula
Klio2033 [76]
Glucose and Galactose both have the same molecular formula, C6H12O6, but in the body, galactose must be first converted to glucose to make energy. The difference<span> is their </span>structures 
3 0
3 years ago
Read 2 more answers
n a gas-phase equilibrium mixture of SbCl5, SbCl3, and Cl2 at 500 K, pSbCl5 = 0.17 bar and pSbCl3 = 0.22 bar. Calculate the equi
Lorico [155]

Answer:

2.7 × 10⁻⁴ bar

Explanation:

Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

Kp = pSbCl₃ × pCl₂ / pSbCl₅

pCl₂ = Kp × pSbCl₅ / pSbCl₃

pCl₂ = 3.5 × 10⁻⁴ × 0.17 / 0.22

pCl₂ = 2.7 × 10⁻⁴ bar

7 0
3 years ago
A 112. 6 g mass of unknown material is submersed in 102 ml of water to yield a final volume of 126 ml. What is the apparent dens
skad [1K]

The density of the unknown material is 0.213 ml/g

<h3>Apparent density of the unknown material</h3>

The apparent density of the unknown material is calculated as follows;

Volume of the unknown substance = 126 ml - 102 ml = 24 ml

Density of the unknown substance = mass/volume

Density of the unknown substance =  24 ml / 112.6 g

Density of the unknown substance = 0.213 ml/g

Thus, the density of the unknown material is 0.213 ml/g

Learn more about density here; brainly.com/question/6838128

#SPJ1                          

4 0
1 year ago
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