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Klio2033 [76]
3 years ago
13

If 0.0262 mol of cacl2 is dissolved in water to make a 0.520 m solution, what is the volume of the solution?

Chemistry
1 answer:
Oduvanchick [21]3 years ago
5 0
Cacl2  dissolve   in  water   according  to the  following  equation

Cacl2 + H2O  =  Ca(OH) + Hcl
Volume=  moles/molarity
  The  reacting  ratio    between CaCl2  to  Ca(OH)  is   1:1
therefore  moles  of  solution   is  also  0.0262  moles hence  volume   is  =
0.0262mol/  0.52mol/l =  0.0504L  or50.4ml
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work out if it's either going to sink or float

Explanation:

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What is the nuclear equation for decay of Am - 241
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1 year ago
If irons temperature goes from 50c to 75c in a 20g sample, how many joules of heat were used?
Marina CMI [18]

Answer:

Option D. 230 J

Explanation:

We'll begin by calculating the temperature change of the iron. This can be obtained as follow:

Initial temperature (T₁) = 50 °C

Final temperature (T₂) = 75 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

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Thus, the temperature change of the iron is 25 °C.

Finally, we shall determine the amount of heat energy used. This can be obtained as follow:

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3 0
3 years ago
Suppose 17. g of hydrochloric cid is mixed with 6.99 g of sodium hydroxide calculate the minimum mass of hydochloric acid taht c
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Answer: 10.62g

Explanation:

First let us generate a balanced equation for the reaction.

HCl + NaOH —> NaCl + H2O

Molar Mass of HCl= 1 + 35.5 = 36.5g/mol

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From the question,

Mass of HCl = 17g

Mass of NaOH = 6.99g

Converting these Masses to mole, we obtain:

n = Mass / Molar Mass

n of HCl = 17/36.5 = 0.4658mol

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From the question,

1 mole of NaOH requires 1mole of HCl.

Therefore, 0.1748mol of NaOH will also require 0.1748mol of HCl.

But we were told that 17g( i.e 0.4658mol) of HCl were mixed.

Therefore, the unreacted amount of HCl = 0.4658 — 0.1748 = 0.291mol

Converting this to mass, we have:

Mass of HCl = n x molar Mass

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Mass of HCl = 10.62g

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8 0
3 years ago
At constant temperature a bicycle tire pump contains 252mL of air at 995kPa pressure. The plunger of the pump is pushed down unt
Novay_Z [31]

Answer:

The new pressure of the pump is 26.05 atm or 2639.4 kPa

Explanation:

Step 1: Data given

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The volume of the pump is reduced to 95.0 mL = 0.095 L

Step 2: Calculate the new pressure

V1*P1 = V2*P2

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⇒with P1 = the initial pressure of the pump = 9.81989 atm = 995 kPa

⇒with V2 = the reduced volume of the pump = 0.095 L

⇒with P2 = the new pressure = TO BE DETERMINED

0.252 L * 9.81989 atm = 0.095 L * P2

P2 = 26.05 atm

The new pressure is 26.05 atm

OR

0.252 L * 995 = 0.095 L * P2

P2 = 2639.4 kPa

The new pressure of the pump is 26.05 atm or 2639.4 kPa

4 0
3 years ago
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