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Phantasy [73]
2 years ago
13

What’s the answer ?

Chemistry
2 answers:
dusya [7]2 years ago
7 0

Answer:

45 kJ

Explanation:

natta225 [31]2 years ago
4 0

Answer:

45 kJ

Explanation:

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__________ ___________ can release different forms of energy such as electricity or light, in addition to the release of heat en
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If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, how would you do it? (Hint: Us
grigory [225]

Answer:

We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to  make 100 mL of a 0.2 M fruit drink solution.

Explanation:

  • Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.

<em>(MV) before dilution = (MV) after dilution.</em>

M before dilution = 1.0 M, V before dilution = ??? mL.

M after dilution = 0.2 M, V after dilution = 100 mL.

<em>∴ V before dilution = (MV) after dilution / M before dilution </em>= (0.2 M)(100 mL) / (1.0 M) = <em>20.0 mL.</em>

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8 0
3 years ago
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Fill in the blank with the correct answer. The longer the handle the __________ the mechanical advantage and the greater the inc
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Greater

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The longer the handle, the greater the mechanical advantage and the greater the increase in force that is applied to the bolt.

Mechanical advantage is the rate at which force is multiplied.

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2 years ago
In the laboratory you are asked to make a 0.565 m sodium bromide solution using 315 grams of water. How many grams of sodium bro
Scorpion4ik [409]

Answer : The mass of sodium bromide added should be, 18.3 grams.

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Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}

Solute is, NaBr and solvent is, water.

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Molality of NaBr = 0.565 mol/kg

Molar mass of NaBr = 103 g/mole

Mass of water = 315 g

Now put all the given values in the above formula, we get:

0.565mol/kg=\frac{\text{Mass of NaBr}\times 1000}{103g/mole\times 315g}

\text{Mass of NaBr}=18.3g

Thus, the mass of sodium bromide added should be, 18.3 grams.

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