<u>Answer:</u> The half life of the given radioactive isotope is 43.86 minutes
<u>Explanation:</u>
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken for decay process = 233 minutes
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount of the reactant = 0.500 M
[A] = amount left after decay process = 0.0125 M
Putting values in above equation, we get:
The equation used to calculate half life for first order kinetics:
where,
= half-life of the reaction = ?
k = rate constant = 
Putting values in above equation, we get:
Hence, the half life of the given radioactive isotope is 43.86 minutes
C. 10 amu i am 100 sure that it is 10 amu
The molar mass is what would you find on the periodic table and it is used in the mole conversions within chemistry. So the answer would have to be A: the mass in grams of one mole of a substance.
Rechargeable batteries use a reversible reaction medium to convert electrical current to a form of chemical energy which can be stored for future use.
<h3>
What is a rechargeable battery?</h3>
A rechargeable battery is a type of battery that can be charged many times by passing electric current through the cells in a reversible reaction.
<h3>How does recahargeable battery store energy?</h3>
When electrical energy from an outside source is applied to a secondary cell (reachargeable battery), the negative to positive electron flow that occurs during discharge is reversed, and the cell's charge is restored. This process is called reversible reaction.
Thus, rechargeable batteries use a reversible reaction medium to convert electrical current to a form of chemical energy which can be stored for future use.
Learn more about reversible reaction here: brainly.com/question/11412193
Answer::
<u><em>Lower rate of reaction</em></u>
Explanation:
Lower concentration of reactant in an experiment is indicative of fewer ions or atoms present, which means a slower rate of reaction. In a titration reaction for instance, the end point would take longer to be substantiated, thereby increasing volume of titres. This is further backed up by collision theory which states that more particles in a system improves combinations of molecules.
This however may not be the case if the iodine in question is catalyst, in which case the change in concentration has no effect whatsoever on the reaction rte.
I hope this explanation fits the brief.
