The correct answer is option B, that is, add 1.46 grams of NaCl to 250 milliliters of H₂O.
First there is a need to find the moles of NaCl in 250 ml of 0.10 M NaCl,
Moles of NaCl = molarity × volume = 0.10 M × (250/1000L) = 0.025 mol
The corresponding mass of NaCl is,
Mass of NaCl = moles × molar mass = 0.025 mol × 58.5 g/mol = 1.46 g
Thus, there is a need to dissolve 1.46 grams of NaCl solid into 50 ml of H₂O and dilute to 250 ml.
Answer: There are three different types of intermolecular forces in terms of strength. They are (strongest to weakest) hydrogen bonding, dipole-dipole and Van der Waals' forces.
Explanation: Mark me brain, give 5 stars and a thank you
Answer:
Two possible compounds are shown below- one with an exocyclic double bond and another one with an endocyclic double bond
Explanation:
Reaction of alkene with 
gives a complex of mercurous ion.
Then water molecule attacks this complex through 
type reaction at more substituted position.
cleaves the resultant C-Hg bond and forms a C-H bond.
Two possible structures of an alkene is possible to yield 1-methylcyclohexanol which are shown below.
Answer:
The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
An ester , propyl methanoate ( HCOOC₃H₇) when reacts with sodium hydroxide( NaOH) forms sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH).
The reaction is as follows:
HCOOC₃H₇+NaOH ⇒HCOONa + C₃H₇OH
So when propyl methanoate is hydrolyzed in water and in NaOH then sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH) forms
