The –OH+ group is most acidic proton in ln-OH as shown in figure (a). The proton is circled in the figure.
The stabilisation of the conjugate base produced is stabilises due to resonance factor. The possible resonance structures are shown in figure (b).
The acidity of a protonated molecule depends upon the stabilisation of the conjugate base produced upon deprotonation. The conjugate base of ln-OH is shown in figure (a).
The possible resonance structures are shown in figure (b). As the number of resonance structures of the conjugate base increases the stabilisation increases. Here the unstable quinoid (unstable) form get benzenoid (highly stable) form due to the resonance which make the conjugate base highly stabilise.
Thus the most acidic proton is assigned in ln-OH and the stability of the conjugate base is explained.
Physical change because ther is force which is the electric current
Answer: 233 L of
will be produced from 150 grams of 
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of
produce = 8 moles of
Thus 2.59 moles of
will produce=
of
Volume of
Thus 233 L of
will be produced from 150 grams of 
Rock that has formed by sediment deposited by water or air
When this is the first order reaction of the radioactive decay:
and according to the first order rate equation:
㏑(Ao/A) = K t
and when Ao = is the starting concentration
and A = is the concentration at time t
and K is the rate constant
t is the elapsed time = 14.26 days
for 1 half-life ∴ Ao/A = 2
by substitution:
㏑2 = K * 14.26 days
∴ K = 0.0486 days^-1