Answer:
No.
Explanation:
During chemical reaction, atomes cannot be created or destroyed, they can only react together to form <em>E</em><em>l</em><em>e</em><em>m</em><em>e</em><em>n</em><em>t</em><em> </em>or <em>C</em><em>o</em><em>m</em><em>p</em><em>o</em><em>u</em><em>n</em><em>d</em><em> </em>at the <em>P</em><em>r</em><em>o</em><em>d</em><em>u</em><em>c</em><em>t</em><em> </em>side.
We need an equation that will relate the concentrated mixture and the diluted one. To solve this we use the equation,
M1 V1 = M2 V2
where M1 is the concentration
of the stock solution, V1 is the volume of the stock solution, M2 is the
concentration of the new solution and V2 is its volume.
M1V1 = M2V2
30 % x 6 oz = 20 % x V2
V2 = 9 oz
The volume of the diluted mixture would be 9 oz. Therefore, you will need to add 9 oz - 6 oz = 3 oz of fruit juice to dilute the 30 percent alcohol to 20 percent alcohol.
Answer:
Copper dicyanide CUPRIC CYANIDE Copper cyanide (Cu(CN)2) Cyanure de cuivre copper (II) cyanide More...
Explanation:
HOPE THIS HELPS :)
We actually don't need the value for temperature. There is a direct formula relating work, pressure and volume. The relationship is:
W = Pexternal(ΔV)
Substituting the values and incorporating the conversion ratio,
W = (1 atm)(6.43 L - 1 L)(101.3 J/1 L·atm)
<em>W = 651.36 J</em>
