For the reaction show below determine the rate law. H2SO3(aq) + 6I-(aq) + 4H+(aq) → S(s) + 2I3- + 3H2O (l) In the presence of a
little starch, this solution turns from colorless to blue when I3- is formed. The following data were obtained: [H2SO3] [H+] [I-] Initial Rate (mol/L s) 1.0 x 10-2 2.0 x 10-1 2.0 x 10-1 1.66 x 10-7 3.0 x 10-2 2.0 x 10-1 2.0 x 10-1 4.98 x 10-7 1.0 x 10-2 1.0 x 10-1 2.0 x 10-1 8.30 x 10-8 1.0 x 10-2 2.0 x 10-1 4.0 x 10-1 13.2 x 10-7 Calculate the rate law for this reaction: rate = k [H2SO3] [H+] [I-
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According to the statement
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid
<h3>What is neutralization?</h3>A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization or neutralization. In a water reaction, neutralization ensures that there is no excess of hydrogen or hydroxide ions in the solution.
<h3>According to the given information:</h3>The equation of the neutralization reaction between H2SO4 and CaCO3.
CaCO3 + H2SO4 → CaSO4 + H2CO3
H2CO3 dissociate to water and carbon dioxide.
CaCO3 + H2SO4 → CaSO4 + H2O + CO2
Now solving for the mass of CaCO3 needed to neutralize the acid.
mass of CaCO3 = 9460 Kg H2SO4 ×
= 21284.56606
mass of CaCO3 = 2.12 x 10^4 lbs
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid.
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