For the reaction show below determine the rate law. H2SO3(aq) + 6I-(aq) + 4H+(aq) → S(s) + 2I3- + 3H2O (l) In the presence of a
little starch, this solution turns from colorless to blue when I3- is formed. The following data were obtained: [H2SO3] [H+] [I-] Initial Rate (mol/L s) 1.0 x 10-2 2.0 x 10-1 2.0 x 10-1 1.66 x 10-7 3.0 x 10-2 2.0 x 10-1 2.0 x 10-1 4.98 x 10-7 1.0 x 10-2 1.0 x 10-1 2.0 x 10-1 8.30 x 10-8 1.0 x 10-2 2.0 x 10-1 4.0 x 10-1 13.2 x 10-7 Calculate the rate law for this reaction: rate = k [H2SO3] [H+] [I-
1 answer:
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Answer:
<h2>0.14 kg</h2>Explanation:
The mass of the ball can be found by using the formula
v is the velocity
k is the kinetic energy
From the question we have
We have the final answer as
<h3>0.14 kg</h3>Hope this helps you
What is the specific heat of a substance whose mass is 7 grams, if it absorbs 180 calories to go from 10 degrees Celsius to 85 degrees Celsius
Answer:
0.343cal/g°C
Explanation:
Given parameters:
Mass of substance = 7g
Quantity of heat absorbed = 180calories
Initial temperature = 10°C
Final temperature = 85°C
Unknown:
Specific heat of the substance = ?
Solution:
To solve this problem, the specific heat of a substance is the amount of heat needed to raise the temperature of a unit mass of that substance by 1°C.
Mathematically;
C =
C is the specific heat
Q is the amount of heat
m is the mass
T is the temperature
1 and 2 are the initial and final states
Now, insert the parameters and solve;
C = = 0.343cal/g°C