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-BARSIC- [3]
4 years ago
11

For the reaction show below determine the rate law. H2SO3(aq) + 6I-(aq) + 4H+(aq) → S(s) + 2I3- + 3H2O (l) In the presence of a

little starch, this solution turns from colorless to blue when I3- is formed. The following data were obtained: [H2SO3] [H+] [I-] Initial Rate (mol/L s) 1.0 x 10-2 2.0 x 10-1 2.0 x 10-1 1.66 x 10-7 3.0 x 10-2 2.0 x 10-1 2.0 x 10-1 4.98 x 10-7 1.0 x 10-2 1.0 x 10-1 2.0 x 10-1 8.30 x 10-8 1.0 x 10-2 2.0 x 10-1 4.0 x 10-1 13.2 x 10-7 Calculate the rate law for this reaction: rate = k [H2SO3] [H+] [I-

Chemistry
1 answer:
alekssr [168]4 years ago
7 0

Answer:

Please see the attached picture for the complete answer.

Explanation:

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3 years ago
In the electrolysis of water, how long will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell thr
vladimir2022 [97]

In the electrolysis of water,  3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.

<h3>What is Ideal Gas Law ?</h3>

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

It is expressed as

PV = nRT

where,

P = Pressure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = Temperature in kelvin

Here,

P = 1.0 atm

V = 165.0 L

R = 0.0821 atm. L/mol.K (Ideal gas constant)

T = 273 K

n = ?

Now put the value in above expression, we get

PV = nRT

1.0 atm × 165.0 L = n × 0.0821 atm. L/mol.K × 273 K

165.0 atm. L = n × 22.4  atm. L/mol

n = \frac{165.0\ \text{atm. L}}{22.4\ \text{atm. L/mol}}

n = 7.36 mol

The reaction is

2H⁺ + 2e⁻ → H₂

1 mol of electrons is produced from 96500 C

So,

96500 \frac{C}{\text{mol} \times e} \times 2e \times 7.36\ \text{mol}

<em>= </em>1,420,480 C

<u>Convert milliampere to C/s</u>

1mA = 0.001 C/s

113.0 mA = 113.0 × 0.001

               = 0.113 c/s

<h3>What is relationship between current, charge and time ?</h3>

The relation between current, charge and time is expressed as:

I = \frac{Q}{t}

where,

I = Current

Q = Charge in Coulomb

t = time

Now put the value in above formula we get

I = \frac{Q}{t}

  = \frac{1,420,480\ C}{0.113\ C/s}

  = 12,570,619.469 s

  = 3490 hour

Thus from the above conclusion we can say that In the electrolysis of water,  3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.

Learn more about the Ideal Gas Law here: brainly.com/question/25290815

#SPJ4

5 0
2 years ago
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