All categories

3 years ago

Select the component form of the vector shown.

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

7 0

In this case always write i before j (because we need to follow the alphabetical order)
You will get 3i + 3j (+3)

so, the answer would be :
<3,6>

Hope this helps

seropon [69]3 years ago

6 0

Answer:

Step-by-step explanation:

Given is a line segment BC in the graph

The coordinates of C is (4,1) and coordinates of B (-2,-2)

In vector form C = 4i+j

B = -2i-2j

Hence vector BC = OC-OB

$= 4i+j-(-2i-2j)\\= 4i+j+2i+2j\\=6i+3j$

You might be interested in

Susie drew the shape with a perimeter of 36 inches then she drew a square one side of the square was x inches What is the perime

tatuchka [14]

Answer:

Step-by-step explanation:

3 0

2 years ago

PLZ HELP ASAP I NEED IT NO LINKS AND PLZ EXPLAIN AWNCER ive tryed and i still dont get it

iVinArrow [24]

The answer to this i believe would be B

3 0

3 years ago

Plot 9/10 and 2 1/5 on the number line

MariettaO [177]

Answer:

I dont know the context of the problem, but to make it easier to plot, you could change 2 1/5 to 2 2/10

hopefully this helps! :)

4 0

2 years ago

A sample of 500 people are asked,"If you could have a new vehicle, would you want asport utility vehicle or a car?" The result o

kykrilka [37]

The complete table would be the follwing:

To get this probability, we take the total number people who pefer an SUV, and divide it by the total number of people in the sample

$P(S)=\frac{210}{500}$

To get this probability, we take the total number of females, and divide it by the total number of people in the sample

$P(F)=\frac{315}{500}$

To get this probability, we take the total number of females who pefer a car, and divide it by the total number of people in the sample

$P(F\cap C)=\frac{263}{500}$

$\begin{gathered} P(F\cup S)=P(F)+P(S)-P(F\cap S) \\ \rightarrow P(F\cup S)=\frac{315}{500}+\frac{210}{500}-\frac{52}{500} \\ \\ \Rightarrow P(F\cup S)=\frac{473}{500} \end{gathered}$

$\begin{gathered} P(S|M)=\frac{P(S\cap M)}{P(S)} \\ \\ \rightarrow P(S|M)=\frac{\frac{158}{500}}{\frac{210}{500}} \\ \\ \Rightarrow P(S|M)=\frac{158}{210} \end{gathered}$

$\begin{gathered} P(M|S)=\frac{P(M\cap S)}{P(S)} \\ \\ \rightarrow P(M|S)=\frac{\frac{158}{500}}{\frac{185}{500}} \\ \\ \Rightarrow P(M|S)=\frac{158}{185} \end{gathered}$

In the final question we're being asked for: