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valentina_108 [34]
3 years ago
8

(a) Calculate the magnitude of the gravitational force exerted by Mars on a 67 kg human standing on the surface of Mars. (The ma

ss of Mars is 6.4 × 1023 kg and its radius is 3.4 × 106 m.)
Physics
1 answer:
Reptile [31]3 years ago
6 0

Answer:

2474.13 N

Explanation:

From Newton's Law of universal gravitation,

F = Gmm'/r².................... Equation 1

Where F = gravitational force, m = mass of the human, m' = mass of mars, G = Gravitational acceleration, r = radius of mars.

Given : m = 67 kg, m' = 6.4×10²³ kg, r = 3.4×10⁶ m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

Substituting into equation 1

F = 67(6.4×10²³)(6.67×10⁻¹¹)/ (3.4×10⁶)²

F = 28600.96×10¹²/11.56×10¹²

F = 2474.13 N.

Hence the gravitational force = 2474.13 N

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Explain Energy Transformation using the image below and how the Law of Conservation of Energy is maintained.
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The chemical energy of petrol is converted to heat energy on combustion. The heat energy is converted to kinetic energy by the use of internal combustion engines in vehicles. The law of conservation of energy is maintained in each process.

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Given is a diagram of energy conversion due to combustion.

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If the half-life of niobium-91 is 680 years, how long will it take for the decay described in the previous question?
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