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valentina_108 [34]
3 years ago
8

(a) Calculate the magnitude of the gravitational force exerted by Mars on a 67 kg human standing on the surface of Mars. (The ma

ss of Mars is 6.4 × 1023 kg and its radius is 3.4 × 106 m.)
Physics
1 answer:
Reptile [31]3 years ago
6 0

Answer:

2474.13 N

Explanation:

From Newton's Law of universal gravitation,

F = Gmm'/r².................... Equation 1

Where F = gravitational force, m = mass of the human, m' = mass of mars, G = Gravitational acceleration, r = radius of mars.

Given : m = 67 kg, m' = 6.4×10²³ kg, r = 3.4×10⁶ m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

Substituting into equation 1

F = 67(6.4×10²³)(6.67×10⁻¹¹)/ (3.4×10⁶)²

F = 28600.96×10¹²/11.56×10¹²

F = 2474.13 N.

Hence the gravitational force = 2474.13 N

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Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

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E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

E = 239.76 N/C

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