What is the change of momentum on a 45,000 kg airplane when it changes its velocity from 242 m/s to 258 m/s?

What game most represents a wave

Julli [10]

Answer:

tipping over dominoes

Explanation:

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6 0

3 years ago

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A 0.110 kg cube of ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.70

Sonbull [250]

Answer:

the distance by which the height of the liquid in the cylinder change after the ice gets melted = 0.528 cm

Explanation:

The change in volume of glycerin when the ice cube is placed on the surface of the glycerin can be represented as:

$V = \frac{m}{ \rho}$

Given that ;

the mass of the ice cube (m) = 0.11 kg = 0.110 × 10³ g

density of the glycerine ( $\rho$ ) = 1.260 kg/L = 1.260 g/cm³

Then:

V = $\frac{0.110*10^3 \ g}{1.260 \ g/cm^3}$

V = $0.0873*10^3 \ cm^3 (\frac{1L}{10^3 cm^3})$

V = 0.0873 L

Now;Initially the volume of the glycerin before the ice cube starts to melt is:

$V_1 = V_i + V\\\\V_1 = V_i+ 0.0873 \ L$

However; the volume of the water produced by the 0.11 kg ice cube = $0.11*10^3 \ cm^3$

The expression for change in the volume of glycerin after the ice cube starts to melt is as follows:

$V_2 = V_i + V"$

replacing $V"$ with $0.11*10^3 \ cm^3$ ; we have:

$V_2 = V_i (0.11*10^3 \ cm^3 )(\frac{1 \ L }{10^3 \ cm^3})$

$V_2 = V_i + 0.11 \ L$

The overall total change in the volume of the glycerin is illustrated as:

$V_f = V_2 - V_1$

Now; from the foregoing ; lets replace the respective value of $V_2$ and $V_1$ in the above equation ; we have;

$V_f = (V_i + 0.11 \ L) - (V_i + \ 00873 \ L)\\ \\V_f = 0.11 L - 0.0873 \ L\\\\V_f = 0.0227 \ L$

The formula usually known to be the volume of a cylinder is :

$V = \pi r ^2 h$

For the question ; we will have:

$V_f = \pi r ^2 h$

making h the subject of the formula ; we have:

$h = \frac{V_f}{\pi r^2}$

replacing 0.0227 L for $V_f$ and the given value of radius which is = 3.70 cm; we have:

$h = \frac{0.0227 \ L ( \frac{10^3 \ cm^3}{1\ L})}{\pi * (3.70 cm)^2}$

$h = \frac{22.7 \ cm^3}{\pi * (3.70 cm)^2}\\\\h = 0.528 \ \ cm$

Thus ; the distance by which the height of the liquid in the cylinder change after the ice gets melted = 0.528 cm

8 0

4 years ago

The bus, at location A, is traveling at 30 m/s when it is shifted to neutral and allowed to

sertanlavr [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The velocity of the bus at B is $v_B= 31.6\ m/s$

Explanation:

Let's take position B as base point .

From the diagram height between point B and A ia mathematically evaluated as

$h_A = 60 -55$

$h_A = 5 \ m$

From the question we are told that

The velocity at location A is $v_A = 30 m/s$

According the law of conservation of energy

$PE_A + KE_A = KE_B$

Where $PE_A$ is the potential energy at A which is mathematically represented as

$PE_A = mgh_A$

$KE_A$ is the kinetic energy energy at A which is mathematically represented as

$KE_A = \frac{1}{2} mv^2_A$

$KE_B$ is the kinetic energy at A which is mathematically represented as

$KE_B = \frac{1}{2} mv_B^2$

Where $v_B$ is the velocity at location B

So

$mgh_A + \frac{1}{2} mv_A^2 = \frac{1}{2} mv_B^2$

Making $v_B$ the subject of the formula

$v_B= \sqrt{\frac{gh_A + \frac{1}{2} v_A^2 }{0.5} }$

Substituting values

$v_B= \sqrt{\frac{(9.8 * 5) + \frac{1}{2} 30^2 }{0.5} }$

$v_B= 31.6\ m/s$

7 0

3 years ago

YO YO I NEED HELP!!!

4vir4ik [10]

Answer: Light energy

Explanation: Light energy is a form of radiant energy that is visible to the human eye.

5 0

3 years ago

A 120-V motor has mechanical power output of 2.20 hp. It is 91.0% efficient in converting power that it takes in by electrical t

Mandarinka [93]

Answer:

a) $i = 15.033\,A$ , b) $\dot E_{in} = 1.804\,kW$ , c) $C = 0.496\,USD$

Explanation:

a) Electric power transmitted into the motor is:

$\dot E _{in} = \frac{(2.20\,hp)\cdot \left(0.746\,\frac{kW}{hp} \right)}{0.91}$

$\dot E_{in} = 1.804\,kW$

The current in the motor is:

$i = \frac{1804\,W}{120\,V}$

$i = 15.033\,A$

b) The energy delivered to the motor is:

$\dot E_{in} = 1.804\,kW$

c) The cost of running the motor for 2.50 hours is:

$C = (1.804\,kW)\cdot (2.5\,h)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(\frac{1}{3600}\,\frac{kWh}{kJ} \right)\cdot \left(0.110\,\frac{USD}{kWh} \right)$

$C = 0.496\,USD$

4 0

4 years ago