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3 years ago

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Una lente forma una imagen de un objeto, el cual está a 16.0 cm de la lente. La imagen está a 12.0 cm de la lente del mismo lado

que el objeto. a) ¿Cuál es la distancia focal de la lente?¿esta es convergente o divergente? b) Si el objeto tiene 8.50 mm de altura, ¿cuál será la altura de la imagen? ¿es derecha o invertida?

1 answer:

Lubov Fominskaja [6]3 years ago

8 0

Answer:

The focal length of the lens is -6.85 cm.

The lens is diverging lens.

The height of the image is 6.4 mm.

Explanation:

Given that,

Object distance = 16.0 cm

Image distance = 12.0 cm

Height of object = 8.50 mm

We need to calculate the focal length of the lens

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Where, v = image distance

u = object distance

Put the value into the formula

$\dfrac{1}{f}=\dfrac{1}{-12}+\dfrac{1}{-16}$

$\dfrac{1}{f}=-\dfrac{7}{48}$

$f=-6.85\ cm$

Focal length is negative so the lens will be diverging lens.

We need to calculate the height of the image

Using formula of magnification

$m=\dfrac{v}{u}=\dfrac{h'}{h}$

Put the value into the formula

$\dfrac{12}{16}=\dfrac{h'}{8.50\times0.1}$

$h'=\dfrac{12}{16}\times8.50\times0.1$

$h'=0.64\ cm$

$h'=6.4\ mm$

Hence, The focal length of the lens is -6.85 cm.

The lens is diverging lens.

The height of the image is 6.4 mm and straight.

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ale4655 [162]

Answer:

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Explanation:

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Pressure is now 5.0 atm

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3 years ago

A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa

bearhunter [10]

Explanation:

Formula which holds true for a leans with radii $R_{1}$ and $R_{2}$ and index refraction n is given as follows.

$\frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

Since, the lens is immersed in liquid with index of refraction $n_{1}$ . Therefore, focal length obeys the following.

$\frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

$\frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

and, $\frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}$

or, $f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}$

$f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}$

= 32.4 cm

Using thin lens equation, we will find the focal length as follows.

$\frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}$

Hence, image distance can be calculated as follows.

$\frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}$

$s_{i} = \frac{fs_{o}}{s_{o} - f}$

$s_{i} = \frac{32.4 \times 100}{100 - 32.4}$

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kati45 [8]

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This usually entail the cultivation of different crops.
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In animal husbandry, some of wastes are used on farm and the excesses from the farm are used to feed livestock.
Sustainable agriculture is a practice of self-reliant agriculture without infringing on the environment.

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polet [3.4K]

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