Question

Una lente forma una imagen de un objeto, el cual está a 16.0 cm de la lente. La imagen está a 12.0 cm de la lente del mismo lado que el objeto. a) ¿Cuál es la distancia focal de la lente?¿esta es convergente o divergente? b) Si el objeto tiene 8.50 mm de altura, ¿cuál será la altura de la imagen? ¿es derecha o invertida?

Answer 1

Answer:

The focal length of the lens is -6.85 cm.

The lens is diverging lens.

The height of the image is 6.4 mm.

Explanation:

Given that,

Object distance = 16.0 cm

Image distance = 12.0 cm

Height of object = 8.50 mm

We need to calculate the focal length of the lens

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Where, v = image distance

u = object distance

Put the value into the formula

$\dfrac{1}{f}=\dfrac{1}{-12}+\dfrac{1}{-16}$

$\dfrac{1}{f}=-\dfrac{7}{48}$

$f=-6.85\ cm$

Focal length is negative so the lens will be diverging lens.

We need to calculate the height of the image

Using formula of magnification

$m=\dfrac{v}{u}=\dfrac{h'}{h}$

Put the value into the formula

$\dfrac{12}{16}=\dfrac{h'}{8.50\times0.1}$

$h'=\dfrac{12}{16}\times8.50\times0.1$

$h'=0.64\ cm$

$h'=6.4\ mm$

Hence, The focal length of the lens is -6.85 cm.

The lens is diverging lens.

The height of the image is 6.4 mm and straight.