Label A-F based on the table using C for concentrated and D for dilute. A 3-column table with 3 rows. Column 1 is labeled Acid s
2 answers:
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Answer: 3) 39.96 amu
Explanation:
Mass of isotope Ar- 36 = 35.97 amu
% abundance of isotope Ar- 36= 0.337% =
Mass of isotope Ar- 38 = 37.96 amu
% abundance of isotope 2 = 0.063 % =
Mass of isotope Ar- 40 = 39.96 amu
% abundance of isotope 2 = 99.600 % =
Formula used for average atomic mass of an element :
Therefore, the average atomic mass of argon is 39.96 amu
Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy