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marusya05 [52]
3 years ago
15

Label A-F based on the table using C for concentrated and D for dilute. A 3-column table with 3 rows. Column 1 is labeled Acid s

lash base with entries upper H c l, Upper N a upper O upper H, Upper H subscript 2 upper S upper O subscript 4. Column 2 is labeled Molarity with entries 12 M and 0.5 M, 0.01 M and 6.0 M, 0.05 M and 10 M. Column 3 is labeled concentrated slash dilute with entries A and B, C and D, E and F.
Chemistry
2 answers:
Agata [3.3K]3 years ago
8 0

Answer : C , D , D , C , D , C

stellarik [79]3 years ago
3 0

Answer:

A) C

B) D

C) D

D) C

E) D

F) C

Explanation:

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Please help i will give brainliest!!! thank you =)
Anastasy [175]

Answer:

Answer choice B. 2

Explanation:

7 0
3 years ago
What sample size (grams) of Na3PO4 (FW 164.00) known to be 50.00% pure should be used to consume exactly 40.00 mL of 0.1000 M HC
Mkey [24]

Answer:

0.109 g.

Explanation:

Equation of the reaction:

Na3PO4 + 3HCl --> 3NaCl + H3PO4

Number of moles of HCl = molar concentration × volume

= 0.1 × 0.04

= 0.004 mol.

By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

= 0.0013 mol

Mass of Na3PO4 = molar mass × number of moles

= 0.0013 × 164

= 0.219 g

Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance

= 0.219 × 50 g/100 g

= 0.109 g.

3 0
3 years ago
Which of the following contains the most atoms?
aksik [14]

Explanation:

9.0122 g be Maybe, sorry i don't think so

8 0
3 years ago
Read 2 more answers
Calculate the average obtained from the following weighings of the same object. Do not forget to include formulas, units, and th
bazaltina [42]

Answer:

10.4376 g

Explanation:

First we <u>calculate the sum of the weighings</u>:

  • 10.4375 g + 10.4381 g + 10.4373 g + 10.4376 g = 41.7505 g

Then we <u>divide the sum by the number of weighings to calculate the average:</u>

  • Number of weighings = 4
  • Average = Sum of weighings / Number of weighings
  • 41.7505 g / 4 = 10.4376 g
6 0
3 years ago
Combustion reactions are exothermic. The heat of reaction for the combustion of 2-methylheptane, C8H18, is 1.306×103 kcal/mol. W
WARRIOR [948]

Answer:

11.45kcal/g

2.612 × 10³ kcal

Explanation:

When a compound burns (combustion) it produces carbon dioxide and water. The combustion of 2-methylheptane can be represented by the following balanced equation:

2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O

It releases  1.306 × 10³ kcal every 1 mol of C₈H₁₈ that is burned.

<em>What is the heat of combustion for 2-methylheptane in kcal/gram?</em>

We know that the molar mass of C₈H₁₈ is 114.0g/mol. Then, using proportions:

\frac{1.306 \times 10^{3}Kcal}{1mol} .\frac{1mol}{114.0g} =11.45kcal/g

<em>How much heat will be given off if molar quantities of 2-methylheptane react according to the following equation? 2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O</em>

In this equation we have 2 moles of C₈H₁₈. So,

2mol \times\frac{1.306 \times 10^{3}kcal }{1mol} =2.612\times 10^{3}kcal

3 0
3 years ago
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