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SashulF [63]
3 years ago
10

As the number of protons increases but the distance between the protons and electron REMAINS THE SAME...

Chemistry
1 answer:
Aloiza [94]3 years ago
8 0

Answer:

The correct option is;

The electronegativity increases

Explanation:

The electronegativity is the measure of an atom's ability to attract a shared electron pair. The electronegativity of an atom is dependent on the atom's atomic number and the separation distance between the electrons in the valence shell and the positively charged nucleus such that an increase in the atomic number results in an increase in electronegativity and an increase in the distance between the valence electrons and the nucleus, leads to a decrease in electronegativity.

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Calculate %ic of the interatomic bonds for the intermetallic compound al6mn. on the basis of this result, what type of interatom
pashok25 [27]

Answer : % ionic character is 0.20%

              Bonding between the two metals will be purely metallic.

Explanation: For the calculation of % ionic character, we use the formula

\% \text{ ionic character}= [1-e^{\frac{-(X_A-X_B)^2)}{4}}]\times(100\%)

where X_A & X_B are the Pauling's electronegativities.

The table attached has the values of electronegativities, by taking the values of Al and Mn from there,

X_{Al}=1.61

X_{Mn}=1.55

Putting the values in the electronegativity formula, we get

\% \text{ ionic character}= [1-e^{\frac{-(1.61-1.55)^2)}{4}}]\times(100\%)

                                               = 0.20%

Now, there are 3 types of inter atomic bonding

1) Ionic Bonding: It refers to the chemical bond in which there is complete transfer of valence electrons between atoms

2) Covalent Bonding: It refers to the chemical bond involving the sharing of electron pairs between 2 atoms.

3) Metallic Bonding: It refers to the chemical bond in which there is an electrostatic force between the positively charged metal ions and delocalised electrons.

In Al_6Mn compound, the % ionic character is minimal that is \sim0.20% and there are two metal ions present, therefore this compound will have metallic bonding.

8 0
3 years ago
The element that has a valence configuration of 5s25p6 is ________.
Ivanshal [37]
Its period 5 from 5s25p6, with Xenon(54) as the noble gas.  2+6 = 8 electrons

54+8 = 62, or Sm.
3 0
2 years ago
What is true about energy in an ordinary chemical reaction? Energy is
Lisa [10]
The answer is statement #3.
4 0
3 years ago
Read 2 more answers
93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0C what would be the volume of this dry gas at STP
Dahasolnce [82]
The  volume  of  the  dry   gas  at     stp  is  calculated as follows

calculate  the  number  on  moles  by use  of   PV =nRT  where  n  is  the number  of  moles

n  is therefore  = Pv/RT
P  = 0.930  atm
R(gas  contant=  0.0821  L.atm/k.mol
V= 93ml  to  liters =  93/1000= 0.093L
T=  10  +  273.15 = 283.15k

n=  (0.930  x0.093)  /(0.0821  x283.15) =  3.  72  x10^-3  moles

At  STp    1  mole  =  22.4L
what about  3.72  x10^-3 moles

by  cross  multiplication

volume =  (3.72  x10^-3)mole  x  22.4L/  1  moles  = 0.083 L   or  83.3 Ml
3 0
3 years ago
If a substance has a half-life of 55.6 s, and if 230.0 g of the substance are present initially, how many grams will remain afte
Assoli18 [71]

Answer:

m=0.127g

Explanation:

Hello,

In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}

In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:

m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g

Best regards.

6 0
3 years ago
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