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2 years ago

As the number of protons increases but the distance between the protons and electron REMAINS THE SAME...

Chemistry

1 answer:

Aloiza [94]2 years ago

8 0

Answer:

The correct option is;

The electronegativity increases

Explanation:

The electronegativity is the measure of an atom's ability to attract a shared electron pair. The electronegativity of an atom is dependent on the atom's atomic number and the separation distance between the electrons in the valence shell and the positively charged nucleus such that an increase in the atomic number results in an increase in electronegativity and an increase in the distance between the valence electrons and the nucleus, leads to a decrease in electronegativity.

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Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho

Zina [86]

Given:

Calculated density values-

Aluminum = 2.7 g/cm3

Copper = 9.0 g/cm3

Iron = 7.9 g/cm3

Titanium = 4.8 g/cm3

Unknown sample mass = 9.5 g

Sample volume = 2.1 cm3

To determine:

The identity of the unknown sample

Explanation:

'Density' is a physical parameter which can be used to identify the nature of the unknown substance.

Density = Mass/Volume

For the unknown sample

Density = 9.5 g/2.1 cm3 = 4.52 g/cm3

This matches closely with the calculated density of titanium

Ans: The unknown substance is made of titanium

4 0

2 years ago

Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit

rosijanka [135]

Explanation:

The relation between $K_a\&K_b$ is given by :

$K_w=K_a\times K_b$

Where :

$K_w=1\times 10^{-14}$ = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = $K_{a1}=1.4\times 10^{-2}$

The value of $K_{b1}$ :

$1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}$

The value of the second ionization constant of sodium sulfite = $K_{a2}=6.3\times 10^{-8}$

The value of $K_{b2}$ :

$1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}$

3 0

3 years ago

I will give 25 points and make them brainlest if they solve this.

sdas [7]

Answer:

Explanation:

7 0

2 years ago

Read 2 more answers

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VikaD [51]

Answer:

thanks for the points

take care bye

6 0

2 years ago

How many days would it take for a crepe myrtle tree to grow 1 cm in height if it grows 3.38 feet per year?

ololo11 [35]

It's very easy, it's depending mainly on converting a mathematical unit:

When 1 Cm = 0.0328084 Ft
So, we assume that:
in 1 year → it grows 3.38 Ft

So X(years)→ 0.0328084

∴X(years) = 0.0328084 * 3.38 = 0.0097 year

We have to convert this unit form years to days by:

1 year = 365 days
So, 0.0097 = X (days)
∴X(days)= 365 * 0.0097 = 3.5 days

So it will take 3.5 days to grow up

7 0

2 years ago