Balance the following chemical equation by providing the correct coefficients.

Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the pr

yuradex [85]

Explanation:

According the equation of Gibb's free energy -

∆G = ∆H -T∆S

∆G = is the change in gibb's free energy

∆H = is the change in enthalpy

T = temperature

∆S = is the change in entropy .

And , the sign of the ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

if

• ΔG < 0 , the reaction is Spontaneous

• ΔG > 0 , the reaction is non Spontaneous

• ΔG = 0 , the reaction is at equilibrium

a.

N₂(g) + H₂(g) → N₂H₄ (g) ; ΔG⁰f = 159.3 kJ/mol

ΔG > 0 , the reaction is non Spontaneous , the reaction is not feasible in the forward direction

b.

2Na(s) + O₂(g) → Na₂O₂ (s) ; ΔG⁰ f = − 447.7kJ/mol

ΔG < 0 , the reaction is Spontaneous , the reaction is feasible in the forward direction .

c.

C(s) + 2S(s) → CS₂ (g) ; ΔG⁰f = 67.1 kJ/mol

ΔG > 0 , the reaction is non Spontaneous , the reaction is not feasible in the forward direction

d.

Ca(s) + 12 O₂ (g) → CaO (s) ; ΔG⁰f = −604.0 kJ/mol

ΔG < 0 , the reaction is Spontaneous , the reaction is feasible in the forward direction .

8 0

3 years ago

pleeeaaaseeeee answer asappppppppp!!!!!!!!!!! Explain the processes of evaporation and condensation using the image above

goldfiish [28.3K]

In the lake that the rivers lead, water molecules evaporate into the sky and form clouds. In the sky, these water droplets condense and form clouds that will eventually rain.

5 0

3 years ago

Read 2 more answers

CH4 + O2 → CO2 + H2O

Scilla [17]

Answer:

9.8 × 10²⁴ molecules H₂O

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Organic

Naming carbons

Stoichiometry

Analyzing reaction rxn
Using Dimensional Analysis

Explanation:

Step 1: Define

[RxN - Unbalanced] CH₄ + O₂ → CO₂ + H₂O

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 130 g CH₄

Step 2: Identify Conversions

Avogadro's Number

[RxN] 1 mol CH₄ → 2 mol H₂O

[PT] Molar Mass of C: 12.01 g/mol

[PT] Molar Mass of H: 1.01 g/mol

Molar Mass of CH₄: 12.01 + 4(1.01) = 16.05 g/mol

Step 3: Stoichiometry

[DA] Set up conversion: $\displaystyle 130 \ g \ CH_4(\frac{1 \ mol \ CH_4}{16.05 \ g \ CH_4})(\frac{2 \ mol \ H_2O}{1 \ mol \ CH_4})(\frac{6.022 \cdot 10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 9.75526 \cdot 10^{24} \ molecules \ H_2O$