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3 years ago

For the following chemical reaction, if 40.0 grams of O2 are completely reacted, how many grams of CO2 will be produced?

Chemistry

1 answer:

e-lub [12.9K]3 years ago

7 0

Hey there!:

Molar mass:

O2 = 31.99 g/mol ; CO2 = 44.01 g/mol

Given the reaction:

C2H4 + 3 O2 --> 2 CO2 + 2 H2O

3 * 31.99 g O2 ------------ 2 * 44.01 g CO2

40.0 g O2 ------------------- mass of CO2 ??

mass of CO2 = 40.0 * 2 * 44.01 / 3 * 31.99

mass of CO2 = 3520.8 / 95.97

mass of CO2 = 36.68 g

Hope that helps!

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tigry1 [53]

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Explanation:

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Examples are:

Level 1 as in 1s

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Level 3 as in 3s 3p 3d

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Level 5 as in 5s .......

Level 6 as in 6s .........

Electrons can be excited to higher energy levels by absorbing energy from the surroundings during chemical reactions and so forming chemical bonds like ionic, covalent etc.

A perfect example is Sodium (Na) and Chlorine (Cl) in Sodium chloride (NaCl)

Sodium has atomic number of 11, so energy level is 1s2, 2s2 2p6, 3s1

Chlorine has atomic number of 17, so energy level is 1s2, 2s2 2p6, 3s2 3p5

You will notice that the both Na and Cl, has electrons in the energy level 3. Then, the bond formed must be one that lead to the formation of a OCTET structure: as in Na gives off its 3s1 electron TO Cl.

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4 years ago

_______ was responsible for first grouping elements into triads based on similar properties.

frez [133]

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3 years ago

Read 2 more answers

How many moles of oxygen atoms are in 7.9E-1 moles of CO_2

Ilya [14]

Answer:

The number of moles of O atom in $(7.9\times10^{-1})$ mol of $CO_{2}$ = 1.6

Explanation:

1 molecule of $CO_{2}$ contains 2 atoms of O

So, $(6.023\times 10^{23})$ molecules of $CO_{2}$ contains $(2\times6.023\times10^{23})$ atoms of O.

We know that 1 mol of an atom/molecule/ion represents $6.023\times10^{23}$ numbers of atoms/molecules/ions respectively.

So, $(6.023\times 10^{23})$ molecules of $CO_{2}$ is equal to 1 mol of $CO_{2}$ .

$(2\times6.023\times10^{23})$ atoms of O is equal to 2 moles of O atom.

Hence, 1 mol of $CO_{2}$ contains 2 moles of O atom.

Therefore, $(7.9\times10^{-1})$ mol of $CO_{2}$ contains $(2\times7.9\times10^{-1})$ moles of O atom or 1.6 moles of O atom.

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