Answer:
more energy is absorbed when the bonds in the reactants are broken
Answer: B: Your ears send a message through the nerves to the brain.
Answer:
T½ = 16hours
Explanation:
Final mass (N) = 10g
Initial mass (No) = 20g
Time (t) = 16hours
T½ = ?
T½ = In2 / λ
But λ = ?
In(N/No) = -λt
In(10/20) = -(λ * 16)
In(0.5) = -16λ
-0.693 = -16λ
λ = 0.693 / 16
λ = 0.0433
Note : λ is known as the disintegration constant
T½ = In2 / λ
T½ = 0.693 / 0.0433
T½ = 16hours
The half-life of the sample is 16hours
1. The atomic number is equal to the number of protons in the nucleus, and the mass number is equal to the number of protons and neutros in the nucleus.
Therefore, to find the number of neutrons we must do mass number - atomic number, which equals 54.
Answer 1: a. 54
2. Atoms of a same element that have a different number of neutrons in the nucleus are called isotopes of an element.
Answer 2: d. Isotopes
3. Potassium has an electron configuration of
, meaning that the first 3 shells are full, and that the last shell (4th one) has only 1 electron.
Answer 3: c. Shells 1, 2 and 3 are full and shell 4 has one electron.
4. An atomic bond isn't a specific bond, it's just a term. Polar covalent and non-polar covalent bonds are strong bonds, which leaves us with the hydrogen bonds, which are indeed the weakest bonds out there.
Answer 4: a. Hydrogen bond
Hope it helped,
BiologiaMagister
Answer:

Explanation:
Hello,
In this case, for the given chemical reaction at equilibrium:

The initial concentration of sulfur trioxide is:
![[SO_3]_0=\frac{0.660mol}{4.00L}=0.165M](https://tex.z-dn.net/?f=%5BSO_3%5D_0%3D%5Cfrac%7B0.660mol%7D%7B4.00L%7D%3D0.165M)
Hence, the law of mass action to compute Kc results:
![Kc=\frac{[SO_2]^2[O_2]}{[SO_3]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BSO_2%5D%5E2%5BO_2%5D%7D%7B%5BSO_3%5D%5E2%7D)
In such a way, in terms of the change
due to the reaction extent, by using the ICE method, it is modified as:

In that case, as at equilibrium 0.11 moles of oxygen are present,
equals:
![x=[O_2]=\frac{0.110mol}{4.00L}=0.0275M](https://tex.z-dn.net/?f=x%3D%5BO_2%5D%3D%5Cfrac%7B0.110mol%7D%7B4.00L%7D%3D0.0275M)
Therefore, the equilibrium constant finally turns out:

Best regards.