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2 years ago

Electrons orbit around the nucleus of atoms in allowed energy states. This is the basis of the theory of which scientist?

Chemistry

1 answer:

VMariaS [17]2 years ago

5 0

Option B. Niels Bohr's model.

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Why is it impossible to have an undiscovered element that would fit between sodium and magnesuim

Stolb23 [73]

Answer:

Sodium has 11 protons and Magnesium has 12. The way that the periodic table is set up doesn't allow for any elements to be in between. The element would have to have 11.5 protons, which is impossible

4 0

2 years ago

Calculate the percentage by mass of the indicated element in the following compounds. Hydrogen in ascorbic acid, HC6H7O6, also k

Scorpion4ik [409]

Answer: The mass percent of hydrogen in ascorbic acid is 4.5 %

Explanation:

In $C_6H_8O_6$ , there are 6 carbon atoms, 8 hydrogen atoms and 6 oxygen atoms.

To calculate the mass percent of element in a given compound, we use the formula:

$\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Molar mass of ascorbic acid}}\times 100$

Mass of hydrogen = $8\times 1g/mol=8g$

Molar Mass of ascorbic acid = $6\times 12g/mol+8\times 1g/mol+6\times 16g/mol=176g$

Putting values in above equation, we get:

$\text{Mass percent of hydrogen}=\frac{8g}{176}\times 100=4.5\%$

Hence, the mass percent of of hydrogen in ascorbic acid is 4.5 %.

8 0

2 years ago

When the following equation is balanced, what is the coefficient for HBr?

deff fn [24]

D.) Balanced equation is Zn + 2HBr - - - > ZnBr2 + H2.

4 0

3 years ago

5 A farmer stopped maintaining a field that was

WARRIOR [948]

Answer: nutrient

Explanation:

5 0

1 year ago

n acid with a pKa of 8.0 is present in a solution with a pH of 6.0. What is the ratio of the protonated to the deprotonated form

Nady [450]

Answer : The ratio of the protonated to the deprotonated form of the acid is, 100

Explanation : Given,

$pK_a=8.0$

pH = 6.0

To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}$

Now put all the given values in this expression, we get:

$6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}$

$\frac{[Deprotonated]}{[Protonated]}=0.01$

As per question, the ratio of the protonated to the deprotonated form of the acid will be:

$\frac{[Protonated]}{[Deprotonated]}=100$

Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100

5 0

2 years ago